休眠新手：多個相關的類

Question

的條件查詢我有兩個類：

@Entity 
@Table(name = "Appeal_Header") 
public class AppealHeader implements Serializable { 

     private static final long serialVersionUID = -8402922611571578104L; 

     @Id 
     @Column(name = "Appeal_Header_Key", unique=true, nullable=false) 
     private long id; 

     @Column(name = "customer_cd", unique=true, nullable=false) 
     private String customer; 

     @ManyToOne(fetch=FetchType.EAGER) 
     @JoinColumn(name="hes_invoice_header_id", insertable=false) 
     private BillingHeader billingHeader; 

     public long getId() { 
      return id; 
     } 

     public void setId(long id) { 
      this.id = id; 
     } 

     public BillingHeader getBillingHeader() { 
      return billingHeader; 
     } 

     public void setBillingHeader(BillingHeader billingHeader) { 
      this.billingHeader = billingHeader; 
     } 

     public String getCustomer() { 
      return customer; 
     } 

     public void setCustomer(String customer) { 
      this.customer = customer; 
     } 

} 


@Entity 
@Table(name = "billing_header") 
public class BillingHeader implements Serializable { 


     private static final long serialVersionUID = 503665425710114912L; 

     @Id 
     @Column(name="hes_invoice_header_id", insertable=false, updatable=false) 
     private long id; 

     @Column(name="claim_number", insertable=false, updatable=false, unique=false) 
     private String claimNumber; 

     @OneToMany(cascade={CascadeType.ALL}) 
     @JoinColumn(name="hes_invoice_header_id", insertable=false, updatable=false) 
     private List<AppealHeader> appealHeader; 

     public long getId() { 
      return id; 
     } 

     public void setId(long id) { 
      this.id = id; 
     } 

     public String getClaimNumber() { 
      return claimNumber; 
     } 

     public void setClaimNumber(String claimNumber) { 
      this.claimNumber = claimNumber; 
     } 

     public List<AppealHeader> getAppealHeader() { 
      return appealHeader; 
     } 

     public void setAppealHeader(List<AppealHeader> appealHeader) { 
      this.appealHeader = appealHeader; 
     } 

} 

public void exececute() { 

Criteria criteria = session.createCriteria(AppealHeader.class); 

    if(!"".equals(form.getCustomer())) 
     criteria.add(Restrictions.eq("customer",form.getCustomer())); 
    if(!"".equals(form.getClaimNumber())) 
     criteria.add(Restrictions.eq("billingHeader.claimNumber",form.getClaimNumber())); 
} 

現在，我執行這個條件查詢：

如果我通過客戶查詢我找回所有的申訴頭記錄加上關聯的帳單標題。但是，如果我查詢客戶和billingHeader.claimNumber只是billingHeader.claimNumber單獨。我得到這個例外：

Exception: org.hibernate.QueryException: could not resolve property: billingHeader.claimNumber of: healthe.appeals.model.AppealHeader 

有人能幫我嗎？

Answer 1

既然你不爲你的Hibernate限制提供的代碼，我已經給你的Hibernate文檔，我認爲這將指向您在正確的方向上的例子：

15.4. Associations

List cats = sess.createCriteria(Cat.class) 
    .add(Restrictions.like("name", "F%")) 
    .createCriteria("kittens") 
     .add(Restrictions.like("name", "F%")) 
    .list();