我想從我的數據庫中提取幾張表並將它們合併爲一個結果查詢。有條件地用SELECT填充列
我有一個products表：
+-----------------+-----------------------------+------+-----+---------+----------------+
| Field | Type | Null | Key | Default | Extra |
+-----------------+-----------------------------+------+-----+---------+----------------+
| id | bigint(20) | NO | PRI | NULL | auto_increment |
| menu_id | bigint(20) | YES | | NULL | |
| menu_is_section | int(1) | NO | | 1 | |
| company_id | bigint(20) | NO | MUL | NULL | |
| name | varchar(255) | NO | | NULL | |
| description | mediumtext | YES | | NULL | |
| image | varchar(255) | NO | | NULL | |
| initial_time | datetime | YES | | NULL | |
| final_time | datetime | YES | | NULL | |
| archived | int(1) | NO | | 0 | |
| full_image | varchar(255) | YES | | NULL | |
| kind | enum('PRODUCT','PROMOTION') | NO | | PRODUCT | |
+-----------------+-----------------------------+------+-----+---------+----------------+
一個product_likes表：
+------------+------------+------+-----+-------------------+-----------------------------+
| Field | Type | Null | Key | Default | Extra |
+------------+------------+------+-----+-------------------+-----------------------------+
| user_id | bigint(20) | NO | MUL | NULL | |
| product_id | bigint(20) | NO | MUL | NULL | |
| liked_on | timestamp | NO | | CURRENT_TIMESTAMP | on update CURRENT_TIMESTAMP |
+------------+------------+------+-----+-------------------+-----------------------------+
而一個users表我想下獲取所有的產品，其唯一的相關領域是id
一個菜單並確定用戶是否「喜歡」該產品。爲此，我正在考慮創建一個新的列來創建一個新列，該列將創建包含1或0的列「likes」，以查看用戶是否喜歡某個產品。
但我有點卡住了，因爲我無法找到有條件地用MySQL填充列的方式。
我的查詢到目前爲止是這樣的：
"SELECT id, name, description, concat('$image_base_url/products/', image) AS icon, concat('$image_base_url/products_full/', full_image) AS full_image FROM (SELECT * FROM products WHERE menu_id = ? AND menu_is_section = ?) AS selected WHERE UTC_TIMESTAMP() BETWEEN initial_time AND final_time ORDER BY initial_time DESC"
而且一切，我需要完成它是尋找如果USER_ID喜歡一個product_it，並創建相應的列。
這樣做的最好方法是什麼？
編輯：
我只是做了LEFT JOIN，我想我越來越接近我想要的東西。 「喜歡」返回1，但我99％肯定這是因爲user_id是1.當用戶不喜歡產品時，它返回NULL。我可以用這個工作，但是如果我的web服務器返回1和0，會更好。
"SELECT selected.id, u_likes.user_id AS liked, selected.name, selected.description, concat('$image_base_url/products/', selected.image) AS icon, concat('$image_base_url/products_full/', selected.full_image) AS full_image FROM (SELECT * FROM products WHERE menu_id = ? AND menu_is_section = ?) AS selected LEFT JOIN (SELECT * FROM product_likes WHERE user_id = ?) AS u_likes ON selected.id = u_likes.product_id WHERE UTC_TIMESTAMP() BETWEEN selected.initial_time AND selected.final_time ORDER BY selected.initial_time DESC"