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給定一個字符串,像這樣:NSRegularExpression,字符串選擇部分
Seat 2: Pet21 ($1.98 in chips)
在PHP中,您可以選擇使用括號在正則表達式正則表達式的一部分,就像這樣:
Seat ([0-9]+): (.{1,12}) .[$|€|£]([0-9]+\.?[0-9]{0,2}) in chips.
這選擇座位號,用戶ID和籌碼數量:
Array
(
[0] => Array
(
[0] => Seat 1: [email protected] ($0.83 in chips)
[1] => Seat 2: Pet21 ($1.98 in chips)
[2] => Seat 3: derphurp ($2.76 in chips)
[3] => Seat 4: -M-A-R-K-qaz ($0.92 in chips)
[4] => Seat 5: Rolle55 ($2.45 in chips)
[5] => Seat 6: SanderDecler ($2 in chips)
)
[1] => Array
(
[0] => 1
[1] => 2
[2] => 3
[3] => 4
[4] => 5
[5] => 6
)
[2] => Array
(
[0] => [email protected]
[1] => Pet21
[2] => derphurp
[3] => -M-A-R-K-qaz
[4] => Rolle55
[5] => SanderDecler
)
[3] => Array
(
[0] => 0.83
[1] => 1.98
[2] => 2.76
[3] => 0.92
[4] => 2.45
[5] => 2
)
)
有沒有辦法做類似的objective-c wi日NSRegularExpression
編輯:到目前爲止,我有這樣的:
NSRegularExpression *regex =
[NSRegularExpression regularExpressionWithPattern:@"Seat [0-9]+: (.{1,12}) .[$|€|£][0-9]+\.?[0-9]{0,2} in chips."
options:0
error:nil];
for (NSTextCheckingResult *result in [regex matchesInString:history options:NSMatchingReportCompletion range:NSMakeRange(0, history.length)])
{
}
這樣做,非常感謝! –
好的答案,小的補充:您需要在字符串中避免反斜槓,即'\ .'應該是'\\。'。 – omz