POST調用「Changelly」 API返回一個HTML頁面，而不是JSON，使用PHP

Question

我試圖實施「Changelly」 API到我的PHP的網站。我嘗試向API發出POST請求以獲取JSON文件作爲響應。我正在使用GUZZLE發出HTTP請求。

這是API指南：https://changelly.com/developers#protocol

這是我的代碼：

<?php 

$uri = 'http://api.changelly.com/'; 

//set api-key and secret 
$key = '7d5dd1b8d9c748559cc7b7f31f6adc37'; 
$secret = 'ca7ccb683f1d6baf4c448136f0cdfa47152814dbe339aacbccbb5568fa600fbe'; 

//API fields and Params 
$message = array(); 
$message['jsonrpc'] = '2.0'; 
$message['method'] = 'getMinAmount'; 
$message['params'] = array('from' => 'LTC', 'to' => 'BTC'); 
$message['id'] = 'test'; 

//serialize the message body 
$data = json_encode($message); 

//sign the data with the key's secret with HMAC-SHA512 
$sign = hash_hmac('SHA512', $data, $secret); 
echo "<br><br>".$sign."<br><br>"; 

//load the API call variables 

//load the composer libraries 
require 'vendor/autoload.php'; 
use GuzzleHttp\Client; 
use GuzzleHttp\Exception\RequestException; 
use GuzzleHttp\Psr7\Request; 

//intialise a guzzle client 
$client = new GuzzleHttp\Client(); 

//create a header 
$head = array('headers' => array('api-key' => $key, 'sign' => $sign, 'Content-Type' => 'application/json', 'Accept' => 'application/json')); 

//execute API call 
$response = $client -> post($uri, $head, $data); 

$json = $response->getBody()->getContents(); 

//dump the result 
var_dump($response); 
echo '<br><br><br>'; 
var_dump($json); 

?> 

'postman' shows the same thing, am I missing something obvious here?

Answer 1

請遵循 「Changelly」 本身共享下面的代碼。

的GitHub代碼Changelly的API在PHP中：

https://github.com/changelly/changelly-examples/blob/master/php/example.php

我已經按照GitHub的代碼對我的作品嚐試了一些方法。 希望它也能爲你工作。 謝謝！