如何選擇今天的記錄來自:如何在cat和grep文件中選擇今天的日期?
Oct 9 21:47:06 server dovecot[1513]: imap([email protected]): Disconnected: Logged out in=235 out=760
Oct 9 21:47:06 server dovecot[1513]: auth-worker(28110): shadow([email protected],127.0.0.1): unknown user
Oct 9 21:47:06 server dovecot[1513]: auth-worker(28110): shadow([email protected],127.0.0.1): unknown user
Oct 9 21:47:06 server dovecot[1513]: imap-login: Login: user=<[email protected]>, method=PLAIN, rip=127.0.0.1, lip=127.0.0.1, mpid=1850, secured, session=<ImGl4XUEHAB/AAAB>
Oct 8 21:47:06 server dovecot[1513]: imap([email protected]): Disconnected: Logged out in=162 out=7805
Oct 8 21:47:08 server dovecot[1513]: auth-worker(28110): shadow([email protected],144.76.43.87): unknown user
Oct 8 21:47:08 server dovecot[1513]: auth-worker(28110): shadow([email protected],144.76.43.87): unknown user
Oct 7 21:47:08 server dovecot[1513]: imap-login: Login: user=<[email protected]>, method=PLAIN, rip=144.76.43.87, lip=144.76.43.87, mpid=1853, secured, session=<gkTD4XUE0QCQTCtX>
Oct 6 21:47:08 server dovecot[1513]: imap([email protected]): Disconnected: Logged out in=235 out=765
Oct 4 21:47:09 server dovecot[1513]: auth-worker(28110): shadow([email protected],127.0.0.1): unknown user
Oct 4 21:47:09 server dovecot[1513]: auth-worker(28110): shadow([email protected],127.0.0.1): unknown user
Oct 4 21:47:09 server dovecot[1513]: imap-login: Login: user=<[email protected]>, method=PLAIN, rip=127.0.0.1, lip=127.0.0.1, mpid=1856, secured, session=<sb/G4XUEIAB/AAAB>
我的命令是:
cat /var/log/maillog | grep imap-login:\ Login | sed -e 's/.*Login: user=<\(.*\)>, method=.*/\1/g' | sort | uniq
偉人,我希望成爲像你這樣的人:)謝謝 – 2014-10-11 13:37:58