正確的php/html參考功能

Question

我得到它這樣的工作 類： class useraccount { private $ username; private $ lastname; private $ firstname;

public function userProfileView() 
    { 
      $varViewUser = mysql_query("SELECT * FROM users"); 
       $varusername = $_SESSION['username']; 
       $varViewUserProfile = mysql_query("SELECT * FROM users WHERE username = '$varusername'"); 
         while ($rows = mysql_fetch_array($varViewUserProfile)) { 
         $this->username = $rows['username']; 
         $this->firstname = $rows['user_firstname']; 
         $this->lastname = $rows['user_lastname']; 
         $this->email = $rows['email']; 
        } 

      return $this->lastname; 
      return $this->firstname; 

    } 
    } 

HTML：

名字：userProfileView（）; ？>

現在我該如何引用要顯示的值？

Answer 1

PHP中的變量始終是本地函數。

建議你重寫

class useraccount{ 


    private $username; 

    public function getUsername() 
    { 
    return $this->username; 
    } 

    public function userProfileView() 
    { 
    while ($rows = mysql_fetch_array($varViewUser)) { 
     $this->username = $rows['username']; 
     $Firstname = $rows['user_firstname']; 
     $lastname = $rows['user_lastname']; 
     $email = $rows['email']; 
    } 
    } 


    include ('user_functions.php') ;$varuser = new useraccount; echo $varuser->getUsername();