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我的簡單的swagger API文檔。參數不傳遞給我的控制器在執行職務,並把操作(Get和刪除操作進行微調)Swagger POST/PUT身體參數沒有傳遞到我的控制器
Swaggerjson文件:
"paths": {
"/api/AddEmployee": {
"post": {
"summary": "Add an Employee",
"description": "Adds a new Employee to the employees list.",
"consumes": [
"application/x-www-form-urlencoded"
],
"parameters": [
{
"name": "body",
"in": "body",
"required": true,
"description": "An Employee to create.",
"schema": {
"$ref": "#/definitions/Employee"
}
}
],
"responses": {
"200": {
"description": "Employee Added Sucessfully"
}
}
}
},
"/api/UpdateEmployee": {
"post": {
"summary": "Update an Employee",
"description": "Updates an exist employee",
"consumes": [
"application/x-www-form-urlencoded"
],
"parameters": [
{
"name": "body",
"in": "body",
"description": "An Employee to be updated.",
"schema": {
"$ref": "#/definitions/Employees"
}
}
],
"responses": {
"200": {
"description": "Employee Added Sucessfully"
}
}
}
}
},
"definitions": {
"Employees": {
"type": "object",
"properties": {
"EmpId": {
"type": "integer",
"format": "int32"
},
"FirstName": {
"type": "string"
},
"LastName": {
"type": "string"
},
"age": {
"type": "integer"
}
}
},
"Employee": {
"Type": "object",
"required": [
"FirstName",
"LastName",
"age"
],
"properties": {
"FirstName": {
"type": "string"
},
"LastName": {
"type": "string"
},
"age": {
"type": "integer"
}
}
}
}
可以在這個問題上的任何一個導向。 TIA!
我想你使用WebApi?如果是這樣,你可以發佈你的控制器,行動和路線細節,你希望收到請求?問題可能在那裏。 –
@PhilCooper更新,你現在可以檢查。 – k11k2