需要日曆天的存儲過程幫助

我困在存儲過程中，我需要一些幫助。我有一個程序，告訴我在兩個日期內有多少個月，每週或每天的日期，但我不知道它是如何計算兩天之間的日差作爲'2015-06-01'和' 2015-06-30'爲此它顯示它是整月或入境是1個月，但'2015-06-01'和'2015-07-01'它顯示1個月和2天。此外，它通過將它們的數字除以7來計算剩餘的幾天，但我想要日曆周。我無法做到這兩件事。需要日曆天的存儲過程幫助

這是代碼 -

CREATE PROCEDURE GetDateParts 
(
@StartDate DATE , 
@EndDate DATE 
) 
AS 
BEGIN 

    /* variables to be used */ 
    DECLARE @Return VARCHAR(5) 
    /* 
     Get the difference between the two dates 
     add 1 to the value to include the first day in the count 
    */ 
    , @TotalNumberOfDays INT 
    , @DaysInMonth TINYINT; 

    /* table variable to store the number of days in a month 
     this would be better as a fixed SQL table as it'll 
     be called a lot */ 
    DECLARE @Months TABLE 
     ([Month] TINYINT, [NoDays] TINYINT); 

    /* month values */ 
    INSERT INTO @Months 
    VALUES 
     (1, 31), 
     (2, 28), 
     (3, 31), 
     (4, 30), 
     (5, 31), 
     (6, 30), 
     (7, 31), 
     (8, 31), 
     (9, 30), 
     (10, 31), 
     (11, 30), 
     (12, 31); 

    /* Create Result table */ 
    DECLARE @ResultTable TABLE ([MonthNumber] TINYINT, [FullMonth] BIT, [Weeks] TINYINT, [Days] TINYINT) 

    -- set the count as the mointh number 
    DECLARE @Count TINYINT = MONTH(@StartDate); 
    SET @TotalNumberOfDays = DATEDIFF(day, @StartDate, @EndDate)+1 
    WHILE @Count <= MONTH(@EndDate) 
    BEGIN 

     /* get the number of days in the month */ 
     SELECT @DaysInMonth = [NoDays] FROM @Months WHERE [Month] = @Count; 

     /* 
     Check if it's a leap year and alter the number of days in Febuary to 29 
     This was taken from https://www.mssqltips.com/sqlservertip/1527/sql-server-function-to-determine-a-leap-year/ 
     */ 
     IF((SELECT CASE DATEPART(mm, DATEADD(dd, 1, CAST((CAST(@StartDate AS VARCHAR(4)) + '0228') AS DATE))) 
       WHEN 2 THEN 1 
       ELSE 0 
       END) = 1) AND MONTH(@StartDate) = 2 
      SET @DaysInMonth = 29; 

     IF (@TotalNumberOfDays >= @DaysInMonth) 
     BEGIN 
      INSERT INTO @ResultTable ([MonthNumber], [FullMonth]) 
      VALUES (@Count, 1) 

      SET @TotalNumberOfDays = @TotalNumberOfDays - (@DaysInMonth-DAY(@StartDate)); 

      SET @StartDate = DATEADD(day, (@DaysInMonth-DAY(@StartDate)+1), @StartDate); 

      SET @Count = @Count + 1; 
     END 
     ELSE IF (@TotalNumberOfDays >= 7) 
     BEGIN 
      INSERT INTO @ResultTable ([MonthNumber], [Weeks]) 
      VALUES (@Count, CAST(@TotalNumberOfDays/7 AS INT)) 
      DECLARE @Remainder TINYINT = @TotalNumberOfDays%7; 

      IF (@Remainder = 0) 
      BEGIN 
       SET @Count = @Count + 1; 
      END 
      ELSE 
      BEGIN 
       SET @TotalNumberOfDays = @Remainder; 
      END 
     END 
     ELSE 
     BEGIN 
      INSERT INTO @ResultTable ([MonthNumber], [Days]) 
      VALUES (@Count, @TotalNumberOfDays) 
      SET @Count = @Count + 1; 
     END 

    END; 

    -- Return Results 
    SELECT * FROM @ResultTable; 
END

誰能幫助，因爲它是對我很重要。 Thnaks提前

來源

2015-10-07 Aditya Shrivastava

可能只是使用函數'datediff（wk，@start，@end）'，'datediff（dd，@start，@end）'？ –

我真的不能使用它，因爲它顯示了一週的差異，即使有4天的日期差異。我只想顯示一週有7天的差異，並且有整整一週，因爲我有數據明智地表示不在分手天數 –

然後使用'datediff（dd，@start，@end）/ 7'作爲周。 –

尋找你的代碼有需要的外部循環爲月的嵌套循環（這將循環通過開始和結束日期之間的月份）和內部WHILE循環將迭代本月的週數也會檢查本週是否已滿，第一天是周開始日期。我們假設星期一的日期。如果不滿足此條件，則將表格填入DayWise Entry。

爲任何查詢進一步評論您的文本。

來源

2015-10-07 11:38:39

是啊那就是我想要的......你能幫我解決嗎？ –

你能幫助我的男人！ –

需要日曆天的存儲過程幫助

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