當我嘗試做一個急切的加載(.WithXyz()
方法)時,我得到了錯誤的數據。它嘗試使用兩個表的主Id進行連接,而不是主表上的「屬性」連接到輔助表的Id。如何在Simple.Data中正確執行加載?
這是我的代碼,在Simple.Data.MySql,或在Simple.Data中的錯誤?
我使用NuGet的Simple.Data(0.18.3.1)和Simple.Data.MySql(0.18.3.0)的版本。
我的代碼:
var traceListener = new SimpleDataTraceListener(); // For logging SQL
Trace.Listeners.Add(traceListener);
var db = Database.Open();
OrderItem orderItem = db.OrderItems
.WithCustomer()
.Get(1)
;
Console.WriteLine(traceListener.Output);
Console.WriteLine(orderItem.Customer.FullName);
下面是SQL的一個例子,我希望:
SELECT orderitem.id,
orderitem.customer_Id,
orderitem.productname,
customer.id AS __with1__Customer__id,
customer.fullname AS __with1__Customer__fullname
FROM orderitem
LEFT JOIN customer ON (orderitem.customer_Id = customer.id)
WHERE orderitem.id = ?p1 LIMIT 0, 1
?p1 (UInt64) = 1
這裏是它實際上是創建SQL的日誌:
select orderitem.id,
orderitem.customer_Id,
orderitem.productname,
customer.id AS __with1__Customer__id,
customer.fullname AS __with1__Customer__fullname
from orderitem
LEFT JOIN customer ON (orderitem.id = customer.id)
WHERE orderitem.id = ?p1 LIMIT 0, 1
?p1 (UInt64) = 1
我的數據:
CREATE TABLE `customer` (
`id` BIGINT(20) NOT NULL AUTO_INCREMENT,
`fullname` VARCHAR(130) NOT NULL,
PRIMARY KEY (`id`),
UNIQUE INDEX `fullname_UNIQUE` (`fullname` ASC)
);
CREATE TABLE `orderitem` (
`id` BIGINT(20) NOT NULL AUTO_INCREMENT,
`customer_Id` BIGINT(20) NOT NULL,
`productname` VARCHAR(130) NOT NULL,
PRIMARY KEY (`id`),
FOREIGN KEY (`customer_Id`) REFERENCES `customer` (`id`)
);
INSERT INTO `customer` (fullname)
VALUES ('wall-E'), ('merlyn'), ('someone');
INSERT INTO `orderitem` (customer_Id, productName)
VALUES (3, 'test item 1'), (2, 'test item 2'), (1, 'test item 3');