SQL查詢開始時間

Question

試圖找到一個查詢來選擇數據，將在特定時間08:00開始，直到第二天08:00，我有單獨的日期和時間字段，並從日期到日期選擇特定的標準。

select * from table 
where datefield between '2014-01-14' and '2014-01-14' 
     and timefield between '08:00' and '08:00' 

Answer 1

不明白爲什麼datefield和timefield不會被保存在一個datetime -column。 此外，我不知道是什麼timefield是的，但如果<和>作品的數據類型，這將工作：

select * from table 
where (datefield = '2014-01-14' and timefield >= '08:00') 
or (datefield = '2014-01-15' and timefield < '08:00') 

編輯：剛剛獲悉你可以一起加入date和time領域的一個datetime

select * from table 
where (datefield + timefield) >= '2014-01-11 08:00' 
and (datefield + timefield) < '2014-01-13 08:00' 

Here's the source of adding them together

Answer 2

declare @from datetime = '2014-01-14 08:00' 
declare @to datetime = '2014-01-15 08:00' 
select * from table 
where datefield between cast(@from as date) and @to 
and not(datefield = cast(@from as date) and timefield < cast(@from as time)) 
and not(datefield = cast(@to as date) and timefield > cast(@to as time))