正則表達式：與他們的IDS

Question

我遇到這種情況，我想知道如果我可以用正則表達式做替換匹配：

我在這個格式的字符串：

{{We all}} love {{stackoverflow}}. 

我的問題是我該如何使用正則表達式替換獲得：

match1 love match2 

Answer 1

s = '{{We all}} love {{stackoverflow}}.' #string to match 
pat = re.compile(r'\{\{.*?\}\}') #pattern 
#now replace each matched group by its index 
for index,group in enumerate(re.findall(pat,s)): 
    s = re.sub(group, 'match'+str(index+1), s) 

適用於任何數量的組。

Answer 2

試試這個

result = re.sub("([{]{2}[^}]+[}]{2})([^{]+)([{]{2}[^}]+[}]{2})", r"match1\2match2", subject) 

解釋

""" 
(   # Match the regular expression below and capture its match into backreference number 1 
    [{]  # Match the character 「{」 
     {2}  # Exactly 2 times 
    [^}]  # Match any character that is NOT a 「}」 
     +   # Between one and unlimited times, as many times as possible, giving back as needed (greedy) 
    [}]  # Match the character 「}」 
     {2}  # Exactly 2 times 
) 
(   # Match the regular expression below and capture its match into backreference number 2 
    [^{]  # Match any character that is NOT a 「{」 
     +   # Between one and unlimited times, as many times as possible, giving back as needed (greedy) 
) 
(   # Match the regular expression below and capture its match into backreference number 3 
    [{]  # Match the character 「{」 
     {2}  # Exactly 2 times 
    [^}]  # Match any character that is NOT a 「}」 
     +   # Between one and unlimited times, as many times as possible, giving back as needed (greedy) 
    [}]  # Match the character 「}」 
     {2}  # Exactly 2 times 
) 
"""