重複功能

Question

from sys import exit 

def answer(): 
    answer = raw_input("> ") 
    if answer == "Yes" or answer == "yes": 
     #going to next 
     joint() 
    elif answer == "No" or answer == "no": 
     print "You still have something, I know..." 
     again() 
    else: 
     fubar() 

def again(): 
    again = raw_input("> ") 
    if again == "Yes" or again == "yes": 
     #going to next 
     joint() 
    elif again == "No" or again == "no": 
     print "You still have something, I know..." 
    else: 
     fubar() 

def fuck(): 
    print "Fubar'd!" 

def joint(): 
    print "To be continue..." 

def question(): 
    print "Hi duuuude..." 
    raw_input("To say 'Hi' press Enter") 
    print "Can you help me?" 
    answer() 

question() 

嗨，你能幫我嗎？當我回答「否」時，我試圖重複「答案」功能。我想逃避功能「再次」...還有一種方法來逃避「答案==」是「或答案==」是「：」所以不管我寫大寫或小寫字母來接受答案，而不是像小菜一樣寫「是」或「是」？

Answer 1

這通常是通過一個while循環來實現的。

編輯：正如指出的那樣，雖然循環很好，清晰，並避免遞歸限制。

沒想到一個簡單的答案會產生這麼多票....

讓我們舉一個例子

while True: 
    ans = raw_input("Enter only y or n to continue").strip().lower() 
    if ans == "y": 
     print "Done!" 
     break 
    elif ans == "n": 
     print "No?" 
    else: 
     print "Not valid input." 

Answer 2

您的問題最簡單的辦法是刪除您again功能，以及遞歸：

def answer(): 
    ans = raw_input("> ") 
    if ans == "Yes" or ans == "yes": 
     #going to next 
     joint() 
    elif ans == "No" or ans == "no": 
     print "You still have something, I know..." 
     answer() # again() 
    else: 
     fubar() 

我不得不將您的answer變量重命名爲ans，以便它不會與函數名稱發生衝突。

---

對於第二個問題，你想要麼：

if answer.lower() == "yes": 

或

if answer in ("Yes", "yes"):