SQL Server中的XML-DML如何與相關的XPath

我有以下數據的XML列的值替換元素值：SQL Server中的XML-DML如何與相關的XPath

<Policy> 
    <Name> 
    <Id>adf</Id> 
    <First>Alan</First> 
    <Last>Turing</Last> 
    </Name> 
    <Name> 
    <Id>asdf</Id> 
    <Business>Vandelay Industries</Business> 
    </Name> 
    <Name> 
    <Id>asdf</Id> 
    <First>Dennis</First> 
    <Last>Ritchie</Last> 
    </Name> 
</Policy>

我將如何編寫XML-DML查詢，將取代的價值所有行中每個Name的Id元素，因此它包含First，Last和Business的值。例如：

<Policy> 
    <Name> 
    <Id>AlanTuring</Id> 
    <First>Alan</First> 
    <Last>Turing</Last> 
    </Name> 
    <Name> 
    <Id>Vandelay Industries</Id> 
    <Business>Vandelay Industries</Business> 
    </Name> 
    <Name> 
    <Id>DennisRitchie</Id> 
    <First>Dennis</First> 
    <Last>Ritchie</Last> 
    </Name> 
</Policy>

這裏是我的失敗嘗試：

update policy set data.modify(' 
    replace value of (//Name/Id/text())[1] 
    with concat(
    (//Name/First/text())[1], 
    (//Name/Last/text())[1], 
    (//Name/Business/text())[1])')

將會產生如下：

<Policy> 
    <Name> 
    <Id>AlanTuringVandelay Industries</Id> 
    <First>Alan</First> 
    <Last>Turing</Last> 
    </Name> 
    <Name> 
    <Id>asdf</Id> 
    <Business>Vandelay Industries</Business> 
    </Name> 
    <Name> 
    <Id>asdf</Id> 
    <First>Dennis</First> 
    <Last>Ritchie</Last> 
    </Name> 
</Policy>

來源

2012-01-20 Seth Reno

這工作。

declare @i int 
declare @maxNames int 
set @i = 1 
set @maxNames = (select max(data.value('count(//Name)', 'int')) from Policy) 
while @i <= @maxNames begin 
    update policy set data.modify(' 
     replace value of (//Name[sql:variable("@i")]/Id/text())[1] 
     with concat(
     (//Name[sql:variable("@i")]/First/text())[1], 
     (//Name[sql:variable("@i")]/Last/text())[1], 
     (//Name[sql:variable("@i")]/Business/text())[1]) 
    ') 
    set @i = @i + 1 
end

來源

2012-01-20 15:54:26

一套基於選擇將是這一個：

update policy 
    set data.modify(' 
    replace value of (//Name[sql:column("id")]/Id/text())[1] 
    with concat(
    (//Name[sql:column("id")]/First/text())[1], 
    (//Name[sql:column("id")]/Last/text())[1], 
    (//Name[sql:column("id")]/Business/text())[1]) 
    ')

來源

2015-11-23 22:43:08

SQL Server中的XML-DML如何與相關的XPath

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