循環一個代碼並按0結束循環

Question

我是新來的，並且是python的初學者，所以請幫助我。我已經完成了以下步驟來創建一個程序，告訴用戶輸入的號碼是從輸入的第一個數字開始，結束還是相同。我的問題是，如何爲它創建一個循環，以便用戶可以輸入儘可能多的數字，然後在輸入0時結束該過程？

---

print ('Please enter your first number') 
firstNumber = input() 

print('Enter the next number(0 to finish)') 
nextNumber=input() 

if firstNumber<nextNumber: 
    print ('Up') 

if firstNumber>nextNumber: 
    print ('Down') 

if firstNumber==nextNumber: 
    print ('Same') 

---

謝謝

Answer 1

從英語翻譯到Python，你想要的是

while nextNumber != 0: 
    ...keep looping... 

因此，在不改變你的代碼太多，你可以簡單地做：

print ('Please enter your first number') 
firstNumber = input() 

print('Enter the next number(0 to finish)') 
nextNumber=input() 

while nextNumber != 0: 

    if firstNumber<nextNumber: 
     print ('Up') 

    if firstNumber>nextNumber: 
     print ('Down') 

    if firstNumber==nextNumber: 
     print ('Same') 

    # turn the nextNumber into the firstNumber 
    firstNumber = nextNumber 

    print('Enter the next number(0 to finish)') 
    nextNumber=input() 

也有可以改進的幾件事情。例如，您不需要在input之前使用print聲明。你可以簡單地做input('Please enter your first number')。此外，您可以使用if - else而不是僅使用if。

這裏是它會是什麼樣子的例子：

firstNumber = input('Please enter your first number') 

nextNumber=input('Enter the next number(0 to finish)') 

while nextNumber != 0: 

    if firstNumber<nextNumber: 
     print ('Up') 

    elif firstNumber>nextNumber: 
     print ('Down') 

    elif firstNumber==nextNumber: 
     print ('Same') 

    # turn the nextNumber into the firstNumber 
    firstNumber = nextNumber 

    nextNumber=input('Enter the next number(0 to finish)') 

---

現在，你說你要收集所有的Ups和Downs並在最後打印出來。您可以簡單地創建一個list並將該值附加到list。像這樣：

ups_and_downs = [] 

firstNumber = input('Please enter your first number') 

nextNumber=input('Enter the next number(0 to finish)') 

while nextNumber != 0: 

    if firstNumber<nextNumber: 
     ups_and_downs.append('Up') 
     print ('Up') 

    elif firstNumber>nextNumber: 
     ups_and_downs.append('Down') 
     print ('Down') 

    elif firstNumber==nextNumber: 
     ups_and_downs.append('Same') 
     print ('Same') 

    # turn the nextNumber into the firstNumber 
    firstNumber = nextNumber 

    nextNumber=input('Enter the next number(0 to finish)') 

print(ups_and_downs) 

Answer 2

nextNumber = 1 #define 
while nextNumber != 0: #as long as its not 0, run loop 
    print ('Please enter your first number') 
    firstNumber = int(input()) #python treats input as str so cast to int 

    print('Enter the next number(0 to finish)')#cast str to int 
    nextNumber= int(input()) 

    if firstNumber<nextNumber: 
     print ('Up') 

    if firstNumber>nextNumber: 
     print ('Down') 

    if firstNumber==nextNumber: 
     print ('Same') 

輸出：

Please enter your first number 
4 
Enter the next number(0 to finish) 
6 
Up 
Please enter your first number 
7 
Enter the next number(0 to finish) 
8 
Up 
Please enter your first number 
5 
Enter the next number(0 to finish) 
4 
Down 
Please enter your first number 
8 
Enter the next number(0 to finish) 
0 
Down 

Answer 3

firstNumber = input('Please enter your first number ') # ask for the first number 
fn = int(firstNumber) # turn into an integer to compare 

while True: # start a loop 
    nextNumber = input('Enter the next number (0 to finish) ') # ask for another number 
    nn = int(nextNumber) 
    if nn == 0: break # leave the loop if the new number is 0 
    if fn<nn: print('Up') # compare 
    if fn>nn: print('Down') 
    if fn==nn: print('Same')