SQL Server 2008中的行select語句算

Question

我有兩個表

TABLE_1：

id pa_name 
1  A 
2  B 
3  C 

TABLE_2：

id breakfast lunch dinner day day_des 
1  Yes  Yes  No  1 des1 
1  No  No  Yes 2 des2 
1  Yes  No  Yes 3 des3 
2  Yes  Yes  Yes 1 des11 
2  Yes  No  No 2 des22 
2  No  Yes  No 3 des33 

我想要的結果一樣，

id pa_name breakfast lunch dinner day_des 
1  A  2  1  2  des1 
2  B  2  2  1  des11 

我正在使用SQL Server 2008

Answer 1

結合與組之間的連接方式：

select t1.id, t1.pa_name, 
     SUM(case when breakfast = 'YES' then 1 end) as breakfast, 
     SUM(case when lunch = 'YES' then 1 end) as lunch, 
     SUM(case when dinner= 'YES' then 1 end) as dinner, 
     MIN(day_des) 
from Table_1 as t1 join Table_2 as t2 on t1.id = t2.id 
group by t1.id, t1.pa_name 

但我有點擔心，最近編輯，怎麼應該，如果有不同的值被拾起day_des？我的選擇是MIN值。

Answer 2

這將使你在逗號值分隔格式

;WITH CTE AS 
(
    SELECT t1.id, t1.pa_name, 
      SUM(CASE WHEN breakfast = 'YES' then 1 end) as breakfast, 
      SUM(CASE WHEN lunch = 'YES' THEN 1 END) AS lunch, 
      SUM(CASE WHEN dinner= 'YES' THEN 1 END) AS dinner  
    FROM Table_1 AS t1 
    JOIN Table_2 AS t2 ON t1.id = t2.id 
    GROUP BY t1.id, t1.pa_name 
) 
SELECT *, 
SUBSTRING(
     (SELECT ', ' + day_des 
     FROM TABLE_2 T2 
     WHERE CTE.id=id 
     FOR XML PATH('')),2,200000) day_des 
FROM CTE 

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