如何使用列表1中元素的索引更改列表2中的索引？

Question

我會用什麼代碼查找猜測在lettersInWord的指數值和改變這些的indeces「 - 」到猜測在lettersDisplayed？

guess = 'o' 
lettersInWord = ['n', 'o', 'o', 'n'] 
lettersDisplayed = ['-', '-', '-', '-'] 

Answer 1

guess = 'o' 
word, disp = ['n', 'o', 'o', 'n'], ['-', '-', '-', '-'] 
print [guess if i == guess else j for i, j in zip(word, disp)] 

輸出

['-', 'o', 'o', '-'] 

Answer 2

指定一個 「空白」 的字符串（在你的情況 「 - 」），然後使用列表理解來改變地方的項目。

guess = 'o' 
blank = '-' 
lettersInWord = ['n', 'o', 'o', 'n'] 

lettersDisplayed = [guess if x == guess else blank for x in lettersInWord] 

print lettersDisplayed # ['-', 'o', 'o', '-'] 
print ''.join(lettersDisplayed) # -oo- 

編輯：注意，這實際上只適用於一個「猜」，如果你想再次它將忽略你最初的猜測。如果你正在尋找多個猜測，那麼請看jonrsharpe的答案。

Answer 3

下面是一個簡單的選擇一些循環：

guess = 'o' 
lettersInWord = ['n', 'o', 'o', 'n'] 
lettersDisplayed = ['-', '-', '-', '-'] 

listOfFinds = [] 
for idx, value in enumerate(lettersInWord): 
    if guess == value: 
     listOfFinds.append(idx) 

for value in listOfFinds: 
    lettersDisplayed[value] = guess 

print lettersDisplayed 

輸出：

['-', 'o', 'o', '-'] 

Answer 4

我假設你想保留先前透露字母disp每個guess。在這種情況下，您可以使用：

blank = '-' 
word = list("noon") 
disp = [blank for char in word] 
for guess in ['m', 'n', 'o']: 
    disp = [w if (d == blank and w == guess) else d 
      for w, d in zip(word, disp)] 
    print(guess, disp) 

這保留了以前的猜測並揭示了新猜出的字母。