計算每個字符串中元音，代詞的數量？

Question

我需要在用戶輸入的字符串的每一行中計算元音，單詞，代詞（「他，她，他們」）的數量。如果輸入是「他們在玩，他在學習」輸出的預期是句子1有3個單詞，有4個元音，1個代詞。 \ n句子2有3個單詞，4個元音，1個代詞。我寫了下面的代碼，但得到一個錯誤意外結束輸入。

string = gets 
string =string.chomp 


sentencecount = 0 
wordcount = 0 
pronouns={"He"=>0,"She"=>0,"They"=>0,"Them"=>0} 
procount=0; 
string.split(".").each do |sentence| 
    wordcount = 0 
    sentencecount += 1  #tracking number of sentences 
    vowels=sentence.scan(/[aeoui]/).count 
    procount=0 
    sentence.split(/\w+/).each do |word| 
    pronouns.each do|key,value| 
     if (key.eq word) 
      procount++ 

    wordcount += 1 # tracking number of words 
    end 

    puts "Sentence #{sentencecount} has #{wordcount} words, has #{vowels} vowels" 
end 

Answer 1

• 你不要在線路
• if年底需要分號需要end（除非它是內嵌形式）
• ++運營商並不在Ruby中

• 存在您將兩個字符串與==運算符進行比較（實際上這是一種方法）

  string = gets.chomp 
  
  sentencecount = 0 
  wordcount = 0 
  pronouns = {"He"=>0, "She"=>0, "They"=>0, "Them"=>0} 
  procount = 0 
  string.split(".").each do |sentence| 
      wordcount = 0 
      sentencecount += 1  #tracking number of sentences 
      vowels = sentence.scan(/[aeoui]/).count 
      procount = 0 
      sentence.split(/\w+/).each do |word| 
      pronouns.each do|key, value| 
       if key == word 
       procount += 1 
       end 
       wordcount += 1 # tracking number of words 
      end 
      end 
  
      puts "Sentence #{sentencecount} has #{wordcount} words, has #{vowels} vowels" 
  end 
  

Answer 2

根據您的初始嘗試，我已經稍微優化了一下，並使它在代碼方面更具可讀性。

string = gets.chomp 
pronouns = ['he', 'she', 'they', 'them'] 
total_word_count = 0 
total_procount = 0 
total_vowel_count = 0 

sentences = string.split(".") 
total_sentence_count = sentences.size 

sentences.each_with_index do |sentence, idx| 
    # VOWELS 
    vowel_count = sentence.scan(/[aeoui]/).count 
    total_vowel_count += vowel_count 

    # WORDS 
    words = sentence.split 
    sentence_word_count = words.size 
    total_word_count += sentence_word_count 

    # PRONOUNS 
    sentence_procount = 0 
    words.each do |word| 
    sentence_procount += 1 if pronouns.include?(word.downcase) 
    end 

    total_procount += sentence_procount 

    puts "Sentence #{idx + 1} has #{sentence_word_count} words, has #{vowel_count} vowels" 
end 

puts "Input has #{total_sentence_count} sentences, #{total_word_count} words, #{total_vowel_count} vowels, and #{total_procount} pronouns" 

Answer 3

我建議你返回一個哈希數組，每行一個，每個哈希包含關聯行的統計信息。然後，您可以使用該數組中的信息來執行所需的操作。

VOWELS = 'aeiou' 
PRONOUNS = %w| he she they them | 
    #=> ["he", "she", "they", "them"] 
PRONOUN_REGEX = /\b#{Regexp.union(PRONOUNS)}\b/ 
    #=> /\b(?-mix:he|she|they|them)\b/ 

def count_em(str) 
    str.downcase.split(/\n/).map { |line| 
    { vowels: line.count(VOWELS), 
     words: line.scan(/[[:lower:]]+/).count, 
     pronouns: line.scan(PRONOUN_REGEX).size } } 
end 

a = count_em "He thought that she thought that he did not know the truth\n" + 
      "René knew she would torment them until they went bananas\n" 
    #=> [{:vowels=>14, :words=>12, :pronouns=>3}, 
    # {:vowels=>15, :words=>10, :pronouns=>3}] 

a.each.with_index(1) { |h,i| 
    puts "In line #{i} there are %d vowels, %d words and %d pronouns" % 
    h.values_at(:vowels, :words, :pronouns) } 
    # In line 1 there are 14 vowels, 12 words and 3 pronouns 
    # In line 2 there are 15 vowels, 10 words and 3 pronouns 

puts "The total number of vowels in all lines is %d" % 
    a.map { |h| h[:vowels] }.reduce(:+) 
    # The total number of vowels in all lines is 29 

這個解決方案是不完整的，因爲它不收縮處理（「不」），所有格（「瑪麗」），縮寫（「1」），英文縮寫和名稱的數字部分（」 J.菲利普（'菲爾'）索薩三世）和其他英語語言的扭曲。