一個字符串中的元音和輔音的Objective-C計數數量

Question

#import <Foundation/Foundation.h> 

int main(int argc, const char * argv[]) 
{ 
    NSString * iphone= @"The designs of the iPhone 6 and iPhone 6 Plus were influenced by that of the iPad Air, with a glass front that is curved around the edges of the display, and an aluminum rear that contains two plastic strips for the antenna; both models come in gold, silver, and space gray finishes"; 

    return 0; 
} 

請幫助我找到不使用數組的Objective-C。

Answer 1

沒人會爲你編碼。所以，你可以嘗試以下步驟：

1. 遍歷字符串

2. 寫元音的條件，並通過1

   增加計數如果（元音） { 計數++ }

3. 最後從字符串長度減去元音計數得到輔音

   NSString * string = @「This是測試字符串「; int count = 0; for（int index = 0; index < string.length; index ++）{ char ch = [string characterAtIndex：index]; if（ch =='a'|| ch =='e'|| ch =='i'|| ch =='o'|| ch =='u'）{ count ++; （@「元音：％d」，count）; NSLog（@「consonants：％d」，string.length - count）;

Answer 2

/* you may check this code may be it will be helpful for you*/ 
#include<stdio.h> 
#include<string.h> 
#include<ctype.h> 
int main() 
{ 
char s[100],ch;/*here declare s[100] as array of character and ch defines the character*/ 
int i,vowel_count,con_count;/* vowel_count and con_count(consonant count) declared here as a integer*/ 
printf("Enter the string\n"); 
gets(s); 
vowel_count = con_count = 0; 
for(i=0;i<strlen(s);i++) 
{ 
    if(isalpha(s[i]))/*here we check that string is alphabet or not*/ 
    { 
     ch = tolower(s[i]);/*conversion of character to small letter*/ 
     if (ch=='a'||ch=='e'|| ch=='i'||ch=='o'||ch=='u')/* check whether the character is vowel or not,(a,e,i,o,u) is vowel*/ 
     vowel_count++;/*if a,e,i,o,u will found in string then vowel count is increased*/ 
     else 
     con_count++;/* if consonant is found then count of consonant will incresde*/ 
    } 
} 
printf("No.of vowels = %d\n",vowel_count); 
printf("No.of consonants=%d\n",con_count); 
}