While循環，打印1到10之間的隨機數和停止時數爲N

Question

這是我得到了什麼，但這只是一次產生一個隨機數，這個數字無限打印：

import random 

x = random.randint(0,10) 
y = 7 
while x != y: 
    print(x) 

Answer 1

你已經基本得到它，你需要生成循環內一個新的隨機數：

import random 

x = random.randint(0,10) 
y = 7 
while x != y: 
    print(x) #Print old (non-7) random number 
    x = random.randint(0,10) #pick a new number. I hope it's 7 so we can end this madness 

print("You found {0}. Congrats. Go have a beer.".format(y)) 

Answer 2

喜歡的東西（移動狀態，而內）：

stop_at = 7 
while True: 
    num = random.randint(0, 10) 
    if num == stop_at: 
     break 
    print num 

或者，一個完整的重新因素：

from itertools import starmap, repeat, takewhile 
from random import randint 

for num in takewhile(lambda L: L != 7, starmap(randint, repeat((0, 10)))): 
    print num