透視表字符串在透視列下分組？

JOB  ENAME 
-------- ---------- 
ANALYST SCOTT 
ANALYST FORD 
CLERK  SMITH 
CLERK  ADAMS 
CLERK  MILLER 
CLERK  JAMES 
MANAGER JONES 
MANAGER CLARK 
MANAGER BLAKE 
PRESIDENT KING 
SALESMAN ALLEN 
SALESMAN MARTIN 
SALESMAN TURNER 
SALESMAN WARD

我想格式化結果設定，使得每個職業都有自己的列：透視表字符串在透視列下分組？

CLERKS ANALYSTS MGRS PREZ SALES 
------ -------- ----- ---- ------ 
MILLER FORD  CLARK KING TURNER 
JAMES SCOTT  BLAKE  MARTIN 
ADAMS    JONES  WARD 
SMITH

我試圖

SELECT ANALYST, CLERK, MANAGER, PRESIDENT, SALESMAN from 
(
    SELECT ename, job from emp 
) as st 
pivot 
(
    SELECT ename 
    FOR job in (ANALYST, CLERK, MANAGER, PRESIDENT, SALESMAN) 
) as pivottable

我得到這些錯誤

Msg 156，Level 15，State 1，Line 7
錯誤的同步在關鍵字'SELECT'附近收稅。
Msg 156，Level 15，State 1，Line 8
關鍵字'in'附近的語法不正確。

如何使用透視將字符串分組在透視列下？

來源

2013-03-11 mr_eclair

@Downvoter關心評論？我的問題沒有什麼是錯的。 – 2013-05-07 13:44:51

當然，這是一個有趣的問題。來自我的+1 ... – 2016-07-01 04:20:40

當您使用PIVOT函數時，您需要使用聚合函數。一個PIVOT的語法是：

從MSDN：

SELECT <non-pivoted column>, 
    [first pivoted column] AS <column name>, 
    [second pivoted column] AS <column name>, 
    [last pivoted column] AS <column name> 
FROM 
    (<SELECT query that produces the data>) 
    AS <alias for the source query> 
PIVOT 
(
    <aggregation function>(<column being aggregated>) 
FOR 
[<column that contains the values that will become column headers>] 
    IN ([first pivoted column], [second pivoted column], 
    ... [last pivoted column]) 
) AS <alias for the pivot table> 
<optional ORDER BY clause>;

一個字符串，你將需要使用任一MIN()或MAX()聚合函數。您將遇到的問題是這些函數將只爲每列返回一個值。

因此，要使PIVOT正常工作，您需要提供一個明確的值，以便在GROUP BY期間保持行分離。

對於你的榜樣，您可以使用row_number()：

SELECT ANALYST, CLERK, MANAGER, PRESIDENT, SALESMAN 
from 
(
    SELECT ename, job, 
    row_number() over(partition by job order by ename) rn 
    from emp 
) as st 
pivot 
(
    max(ename) 
    FOR job in (ANALYST, CLERK, MANAGER, PRESIDENT, SALESMAN) 
) as pivottable

見SQL Fiddle with Demo。

的row_number()創建分配給每個行的job，當你應用聚合函數，並在PIVOT你仍然會得到不同的行的GROUP BY一個獨特的價值。

來源

2013-03-11 11:25:07 Taryn

透視表字符串在透視列下分組？

回答

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