檢查我的邏輯錯誤，請

Question

如果輸入x = y + 5

，輸出必須是：

Token 1 is x is identifier 
Token 2 is = 
Token 3 is y is identifier 
Token 4 is + 
Token 5 is 5 

，這是我沒有我不知道什麼是錯在我，如果條件代碼！

char[] ident = {'x','y','z','a','b','c','k'}; 

Scanner sc = new Scanner(System.in); 
System.out.println("Please Enter Your String"); 
String x = sc.nextLine(); 


StringTokenizer t = new StringTokenizer(x); 

for (int k = 0; k < ident.length; k++) { 
    for (int j = 1; j < x.length()+1; j++) { 
     char m = x.charAt(j); 


     if (m==ident[k]) { 

      System.out.println("Token " + j + " is " + t.nextToken()+" is identifier"); 

     } else { 
      System.out.println("Token " + j + " is " + t.nextToken()); 
     } 

    } 

} 

Answer 1

你不需要兩個循環nether StringTokenizer。你可以這樣做：

final String str = new String(ident); 
char m; 
for (int j = 0; j < x.length(); j++) { 
    m = x.charAt(j); 
    if (str.indexOf(m) >= 0) { 
     System.out.println("Token " + j + " is " + m+" is identifier"); 
    } else { 
     System.out.println("Token " + j + " is " + m); 
    } 
}