1
Sql Server 2008 Datediff帶有select語句中的條件。datediff帶有選擇條件的條件
我有下面的查詢,需要幫助理解爲什麼我得到這些結果和我的問題的最佳解決方案。
SELECT DISTINCT l.program, l.id
,(DATEDIFF(DAY, B.FIRST_DT , B.FIRST_second_DT))days_between1
,(DATEDIFF(DAY, C.FIRST_DT , C.FIRST_second_DT))days_between2
FROM l
LEFT JOIN l B ON L.id = B.id AND L.SERVICE_DATE = B.SERVICE_DATE
AND B.FIRST_DT IS NOT NULL AND B.FIRST_DT IS NOT NULL
AND l.IS ='0' AND L.FIRST_V_DT IS NOT NULL
LEFT JOIN l C ON L.id = C.id AND L.SERVICE_DATE = C.SERVICE_DATE
AND C.FIRST_DT IS NOT NULL
AND C.FIRST_A_DT IS NOT NULL AND L.IS ='1'
AND L.FIRST_DT IS NOT NULL
WHERE 1=1
我得到兩條線
Program id daysbetween1 daysbetween2
blue 1 null 3
blue 1 4 null
如何獲取一條線,如下圖所示,爲什麼我會收到兩行呢?
Program id daysbetween1 daysbetween2
blue 1 4 3
示例數據將有助於此處。 http://stackoverflow.com/help/how-to-ask –
當然,你會得到不同的行,要麼L.IS ='0'或L.IS ='1'... – jarlh
是要做我的L .IS = 0 AND L.IS = 1和我的內部聯接。我將處理樣本數據。 –