bash，shell腳本參數跳過腳本的一部分

Question

我有一個使用case語句完成主菜單的腳本。腳本運行，歡迎屏幕信息回顯至屏幕，用戶點擊進入以清除歡迎屏幕內容（空讀取語句），用戶被要求輸入與菜單項目相對應的編號（讀取菜單編號）。它可以正常工作，但我想稍微擴展功能，並允許用戶跳過歡迎屏幕，並在運行腳本時使用參數直接進入菜單項。

例如，如果我的菜單是：1）文件操作2）用戶信息3）進程，那麼我希望用戶在控制檯中鍵入「scriptfile.sh文件」直接進入文件菜單。這會以某種方式分配menuNum = 1。

我不知道這是可能的使用輸入重定向，或者真的如果可能的話。任何幫助或提示將不勝感激。謝謝。

基本上，這是我的腳本：

#!/bin/bash 
#DEFINE ARGUMENTS 
if [[ "$1" = "man" ]]; then man ./manpage.txt; exit; fi #argument "man" opens man page, closes main script 
if [ "$1" = "debug" ] 
    then clear 
    echo -e "This area provides debug information:\n" 
    echo -e "There's a lot here, but it's not related to my question." 
    echo -e "\nPress [Enter] to continue." 
    read 
fi 
if [[ "$1" = "file" ]]; then bash tsharonfp.sh < 1; exit; fi #go straight to file menu 
if [[ "$1" = "user" ]]; then bash tsharonfp.sh < 2; exit; fi #go straight to user menu 
if [[ "$1" = "info" ]]; then bash tsharonfp.sh < 3; exit; fi #go straight to info menu 
if [[ "$1" = "fun" ]]; then bash tsharonfp.sh < 4; exit; fi #go straight to fun menu 
if [[ "$1" = "process" ]]; then bash tsharonfp.sh < 5; exit; fi #go straight to proc menu 
#/DEFINE ARGUMENTS 
clear 
echo -e "My script title, contact info, and other stuff gets printed to screen here." 
read #hitting enter clears welcome screen stuff  
clear 
while : #opens while1 loop 
do #while1 loop 
echo -e "Main Menu\n" 
echo -e "[1] File Menu\n[2] User Menu\n[3] Info Menu\n[4] Fun Menu\n[5] Process Menu\n[88] Exit\n[99] Shutdown" 
echo -ne "\nEnter Choice: " 
read menuNum 

case $menuNum in #open mainmenu case 
    1) #File;; #statement isn't commented, of course, but you get the idea 
    2) #user;; 
    3) #info;; 
    4) #fun;; 
    5) #proc;; 
    88) exit;; 
    99) shutdown -h;; 
    *) echo "invalid input";; 
esaC#closes mainmenu case 
done #closes while1 loop 

Answer 1

短短几年的變化需要你的問題的關心。根據參數設置menuNum，如果沒有設置，只詢問/閱讀。

#!/bin/bash 
#DEFINE ARGUMENTS 
if [[ "$1" = "man" ]]; then man ./manpage.txt; exit; fi #argument "man" opens man page, closes main script 
if [ "$1" = "debug" ] 
    then clear 
    echo -e "This area provides debug information:\n" 
    echo -e "There's a lot here, but it's not related to my question." 
    echo -e "\nPress [Enter] to continue." 
    read 
fi 


if [ "$1" = "file" -o "$1" = "1" ]; then menuNum=1; 
elif [ "$1" = "user" -o "$1" = "2" ]; then menuNum=2; 
elif [ "$1" = "info" -o "$1" = "3" ]; then menuNum=3; 
elif [ "$1" = "fun" -o "$1" = "4" ]; then menuNum=4; 
elif [ "$1" = "process" -o "$1" = "5" ]; then menuNum=5; 
else menuNum=0; fi 

#/DEFINE ARGUMENTS 
clear 
echo -e "My script title, contact info, and other stuff gets printed to screen here." 
[ $menuNum = 0 ] && read #hitting enter clears welcome screen stuff  

clear 
while : #opens while1 loop 
do #while1 loop 
echo -e "Main Menu\n" 
echo -e "[1] File Menu\n[2] User Menu\n[3] Info Menu\n[4] Fun Menu\n[5] Process Menu\n[88] Exit\n[99] Shutdown" 
echo -ne "\nEnter Choice: " 
[ $menuNum = 0 ] && read menuNum 

case $menuNum in #open mainmenu case 
    1) #File;; #statement isn't commented, of course, but you get the idea 
    2) #user;; 
    3) #info;; 
    4) #fun;; 
    5) #proc;; 
    88) exit;; 
    99) shutdown -h;; 
    *) echo "invalid input";; 
esaC#closes mainmenu case 
menuNum=0 
done #closes while1 loop