mysql_fetch_assoc和JOIN和回聲

Question

我有2個表用戶和郵件： 用戶包含id，fullname，email，password
和消息包含id，sender，receiver，link

我想讀的所有鏈接接收者（用戶id）其中它等於email和echo發送者和接收者的全名和鏈接。

任何人都請，我對此有點新鮮感？使用`顯示創建表tablename`查詢的輸出

$sql = mysql_fetch_assoc("SELECT m.sender,m.receiver, m.link, u.fullname, u.email 
         FROM `users` AS u 
         JOIN `messages` AS m ON m.receiver = u.id 
         WHERE u.email = '$email'"); 

echo $sql['sender']; 

Answer 1

$query = "SELECT m.sender,m.receiver, m.link, u.fullname, u.email 
        FROM `users` AS u 
        JOIN `messages` AS m ON m.receiver = u.id 
        WHERE u.email = '" . $email . "'"; 

$result = mysql_query($query); 
while($row = myslq_fetch_assoc($result)) { 
    echo $row['sender']; 
}