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我想從我的數據庫中獲取一些數據,但mysqli fetch()函數沒有獲取/不工作,它返回false。下面是我正在使用的功能,請幫助。mysqli fetch()不提取
public function return_track_order_details($adRef,$transaction_id){
$db = parent::Connect_Database();
$stmt = $db->prepare("SELECT * FROM `s_b_p_h` WHERE `ad_reference` = ? AND `transaction_id` = ? LIMIT 1 ");
$stmt->bind_param('ss',$adRef,$transaction_id);
$stmt->execute();
$stmt->bind_result(
$id,
$date,
$name,
$email,
$phone,
$full_address,
$total_amount_paid,
$buyers_account_id,
$sellers_account_id,
$ad_reference,
$transaction_id,
$status_by_buyers,
$status_by_sellers,
$net_status
);
if($stmt->fetch()){
$id = $this->xss_clean($id);
$date = $this->xss_clean($date);
$name = $this->xss_clean($name);
$email = $this->xss_clean($email);
$phone = $this->xss_clean($phone);
$full_address = $this->xss_clean($full_address);
$total_amount_paid = $this->xss_clean($total_amount_paid);
$buyers_account_id = $this->xss_clean($buyers_account_id);
$sellers_account_id = $this->xss_clean($sellers_account_id);
$ad_reference = $this->xss_clean($ad_reference);
$transaction_id = $this->xss_clean($transaction_id);
$status_by_buyers = $this->xss_clean($status_by_buyers);
$status_by_sellers = $this->xss_clean($status_by_sellers);
$net_status = $this->xss_clean($net_status);
}else{
return false;
}
}
我做錯了什麼事?
我已經使用過,還檢查我的陳述是否正確,並檢查它是否執行。
您的數據庫調用沒有任何錯誤處理。在這個腳本的頂部,看看是否拋出異常:'mysqli_report(MYSQLI_REPORT_STRICT);' – jeroen 2014-08-30 00:10:20