使用QRegExp替換QString中的單詞

Question

我有一個包含保留字列表的QString。我需要解析另一個字符串，搜索任何包含在第一個字詞中的字詞，並用'\'作爲前綴並修改這些字符。

例子：

QString reserved = "command1,command2,command3" 

QString a = "\command1 \command2command1 \command3 command2 sometext" 

parseString(a, reserved) = "<input com="command1"></input> \command2command1 <input com="command3"></input> command2 sometext" 

我知道我必須使用QRegExp，但我沒有找到如何使用QRegExp檢查，如果一個詞在我宣佈名單。你們能幫我嗎？

在此先感謝

Answer 1

我的reservedWords列表分成QStringList然後遍歷每個保留字。然後，您預先輸入\字符（它需要在QString中轉義），並使用indexOf()函數查看輸入字符串中是否存在該保留字。

void parseString(QString input, QString reservedWords) 
{ 
    QStringList reservedWordsList = reserved.split(','); 
    foreach(QString reservedWord, reservedWordsList) 
    { 
     reservedWord = "\\" + reservedWord; 
     int indexOfReservedWord = input.indexOf(reservedWord); 
     if(indexOfReservedWord >= 0) 
     { 
      // Found match, do processing here 
     } 
    } 
} 

Answer 2

如果你想要做QRegEx這項工作，這裏是代碼：

QString reservedList("command1,command2,command3"); 

QString str = "\\command1 \\command2command1 \\command3 command2 sometext"; 

QString regString = reservedList; 
regString.prepend("(\\\\");  \\ To match the '\' character 
regString.replace(',', "|\\\\"); 
regString.append(")");   \\ The final regString: (\\\\command1|\\\\command2|\\\\command3) 
QRegExp regex(regString); 
int pos = 0; 

while ((pos = regex.indexIn(str, pos)) != -1) { 
    qDebug() << regex.cap(0); 
    pos += regex.matchedLength(); 
} 

Answer 3

我可以幫你用下面的代碼：

QString string1 = "a b c d e f g h i j k l m n o p q r s t u v w y z"; 
QRegExp regExp("(a|e|i|o|u|y)");//letters to be escaped with a backslash, brackets are used to capture the regular expressions in the current string 
string1.replace(regExp,"(\\1)");//Puts each letter a, e, i, o, u, y in brackets 
//string1=="(a) b c d (e) f g h (i) j k l m n (o) p q r s t (u) v w (y) z" 
string1 = "a b c d e f g h i j k l m n o p q r s t u v w y z"; 
QRegExp regExp2("a|e|i|o|u|y"); 
string1.replace(regExp2,"(\\1)");//Replace each letter a, e, i, o, u, y by the string (\1) 
//string1=="(\1) b c d (\1) f g h (\1) j k l m n (\1) p q r s t (\1) v w (\1) z" 

在您的情況：

QString reserved = "command1,command2,command3"; 
QString copyOfReserved = reserved; 
copyOfReserved.replace(",","|"); 
//copyOfReserved == "command1|command2|command3" 
copyOfReserved = "\\b("+copyOfReserved+")\\b"); 
//copyOfReserved == "\b(command1|command2|command3)\b" 
QString a = "\\command1 \\command2command1 \\command3 command2 sometext"; 
QString b = a; 
b.replace(QRegExp("\\\\(" + copyOfReserved + ")"),"<input com=\"\\1\"></input>"); 
//b == "<input com="command1"></input> \command2command1 <input com="command3"></input> command2 sometext" 

我希望我幫你。