確切使用單詞替換陣列

Question

我有值和鏈接的數組，並需要在與該鏈接的內容替換的確切值只有一次。 對於此的preg_replace可以幫助像：

Array ( 
[0] => Array ([keyword] => this week [links] => http://google.com) 
[1] => Array ([keyword] =>this [links] => http://yahoo.com) 
[2] => Array ([keyword] => week [links]=> http://this-week.com)) 
) 

的文字是：

$content = "**This week** I'd like to go to the seaside, but the weather is not good enough. Next **week** will be better. **This** is a kind of great news.**This week** I'd like to go to the seaside, but the weather is not good enough. Next **week** will be better. **This** is a kind of great news.**This week** I'd like to go to the seaside, but the weather is not good enough. Next **week** will be better. **This** is a kind of great news."; 

我試圖用繩子做更換 - 爲陣列可用於字符串替換，但後來所有的出現次數被替換。 我試圖用substr_replace，有位置，但它不工作，我想是。

$pos = strpos($content,$keyword); 
if($pos !== false){ 
    substr_replace($content,$link,$pos,strlen($keyword)); 
} 

和preg_replace函數，用循環數組：

preg_replace('/'.$keyword.'/i', $link, ($content),1); 

這是一種工作，它會替換一次與鏈接的關鍵字，但是如果關鍵字（本週）的化合物，它這和本週，這是錯誤的...

希望你的幫助......謝謝。

更新

$環節是問題 - 如果它是沒有的「http：//」正常工作...... 現在，這是受到質疑，怎麼逃生呢？

Answer 1

如果你會，而不是鏈接使用某種類型的「ID」的，在preg_replace函數使用它，當做到這一點，你可以調用str_replace函數與實際的聯繫取代IDS？

$content = preg_replace('/'.$keyword.'/i', $IDS, ($content),1); 
$content = str_replace($IDS, $link, $content); 

Answer 2

我編寫了代替所有值的代碼示例。我不知道你想要所以我把樣品文本完全相同的文本被替換什麼

$content = "**This week** I'd like to go to the seaside, but the weather is not good enough. Next **week** will be better. **This** is a kind of great news.**This week** I'd like to go to the seaside, but the weather is not good enough. Next **week** will be better. **This** is a kind of great news.**This week** I'd like to go to the seaside, but the weather is not good enough. Next **week** will be better. **This** is a kind of great news."; 
$replacement = array('[linkthiswWeek]', '[links_this]','[links_Week]'); 
$patterns = array('/This week/', '/This/', '/week/'); 
echo preg_replace($patterns, $replacement, $content); 

OUTPUT：

**[linkthiswWeek]** I'd like to go to the seaside, but the weather is not good enough. Next **[links_Week]** will be better. **[links_this]** is a kind of great news.**[linkthiswWeek]** I'd like to go to the seaside, but the weather is not good enough. Next **[links_Week]** will be better. **[links_this]** is a kind of great news.**[linkthiswWeek]** I'd like to go to the seaside, but the weather is not good enough. Next **[links_Week]** will be better. **[links_this]** is a kind of great news. 

您可以通過對矯正$replacement陣列更換適合您的需要

Answer 3

羅伯特的答案的作品，但代替每一次出現，這是不需要的。在preg替換結尾添加'，1'只會替換一次。

例如echo preg_replace（$ patterns，$ replacement，$ content，1）;