周曆減去週日

Question

我從這裏驗證碼：Creation of weekly calender in php

我的問題是，我怎麼讓它落得只有星期六有空嗎？

<?php 
    $dt = new DateTime; 
    if (isset($_GET['year']) && isset($_GET['week'])) { 
     $dt->setISODate($_GET['year'], $_GET['week']); 
    } else { 
     $dt->setISODate($dt->format('o'), $dt->format('W')); 
    } 
    $year = $dt->format('o'); 
    $week = $dt->format('W'); 
?> 

<center> 
<a href="<?php echo $_SERVER['PHP_SELF'].'?week='.($week-1).'&year='.$year; ?>" style="padding-right: 600px">Previous Week</a> <!--Previous week--> 
<a href="<?php echo $_SERVER['PHP_SELF'].'?week='.($week+1).'&year='.$year; ?>" style="padding-left: 600px">Next Week</a> <!--Next week--> 
</center> 

<table border="1" style="text-align: center" align="center"> 
    <col width="100px" /> 
    <col width="200px" /> 
    <col width="200px" /> 
    <col width="200px" /> 
    <col width="200px" /> 
    <col width="200px" /> 
    <col width="200px" /> 
    <tr> 
     <td>Time</td> 
    <?php 
     do { 
      echo "<td>" . $dt->format('l') . "<br>" . $dt->format('F d') . "</td>\n"; 
      $dt->modify('+1 day'); 
     } while ($week == $dt->format('W')); 
    ?> 

Answer 1

通過更換這個解決：

do { 
    echo "<td>" . $dt->format('l') . "<br>" . $dt->format('F d') . "</td>\n"; 
    $dt->modify('+1 day'); 
} while ($week == $dt->format('W')); 

這樣：

for($day=1;$day<=6;$day++){ 
    echo "<td>" . $dt->format('l') . "<br>" . $dt->format('F d') . "</td>\n"; 
    $dt->modify('+1 day'); 
} 

：d