LEFT JOIN表和和值是REGEXP特定字符

Question

我有3個表，這裏是我的表1，會員：

 
+---------+ 
| user_id | 
+---------+ 
|  1 | 
+---------+ 

和我的表2，Members7：

 
+---------------+---------------------------+---------+ 
| TotalWorkYear |   JobScope   | user_id | 
+---------------+---------------------------+---------+ 
|    1 | Financial;pharmacy  |  1 | 
|    6 | Doctor/Diagnosis;pharmacy |  1 | 
|   10 | Accounting;pharmacy  |  1 | 
+---------------+---------------------------+---------+ 

而且表3，Members7_2：

 
+-----------------+----------------+---------+ 
| TotalWorkYear_2 | KnowledgeSkill | user_id | 
+-----------------+----------------+---------+ 
|    1 | abc;def;  |  1 | 
|    6 | vw;xyz;def  |  1 | 
|    10 | vw;xyz;  |  1 | 
+-----------------+----------------+---------+ 

我需要找出USER_ID 是正則表達式 '藥房' 在的，總年的JobScope該正則表達式藥房是> = 0，在Members7_2KnowledgeSkill 並且還正則表達式「DEF」，並且總年的KnowledgeSkill該正則表達式「DEF」是> = 0，

所以現在我們可以看到：

TotalWorkYear = 17 

TotalWorkYear_2 = 7 

user_id = '1' 

這裏是我的查詢：

 
SELECT Members.user_id, 
SUM(IF(Members7.JobScope 
REGEXP 'Pharmacy', Members7.TotalWorkYear, 0)) yearsJobScope, Members7.JobScope AS JobScope, 
SUM(IF(Members7_2.KnowledgeSkill 
REGEXP 'def', Members7_2.TotalWorkYear_2, 0)) yearsSkill, Members7_2.KnowledgeSkill AS KnowledgeSkill 
FROM Members 
LEFT JOIN Members7 ON Members.user_id = Members7.user_id 
LEFT JOIN Members7_2 ON Members.user_id = Members7_2.user_id 
GROUP BY JobScope REGEXP 'Pharmacy', 
KnowledgeSkill REGEXP 'def', user_id 
HAVING 
JobScope REGEXP 'Pharmacy' 
AND yearsJobScope >=0 
AND KnowledgeSkill REGEXP 'def' 
AND yearsSkill >=0 

，但輸出爲：

 
+---------------+------------+ 
| yearsJobScope | yearsSkill | 
+---------------+------------+ 
|   17 |  18 | 
+---------------+------------+ 

，如果我下已經移除了REGEXP，我可以看到：

 
+---------+---------------+---------------------------------------------+------------+----------------+ 
| user_id | yearsJobScope |     JobScope     | yearsSkill | KnowledgeSkill | 
+---------+---------------+---------------------------------------------+------------+----------------+ 
|  1 |    1 | Audit & Taxation;Banking/Financial;pharmacy |   6 | vw;xyz;def  | 
|  1 |    6 | Doctor/Diagnosis;pharmacy     |   6 | vw;xyz;def  | 
|  1 |   10 | General/Cost Accounting;pharmacy   |   6 | vw;xyz;def  | 
+---------+---------------+---------------------------------------------+------------+----------------+ 

好像只是總結3 TotalWorkYears行。

有什麼方法可以解決它嗎？

Answer 1

您左側的多個表加入會使一些技能不止一次地計數。重寫查詢的簡單方法是使用其他表的子查詢;

SELECT m.user_id, yearsjobscope, yearsskill 
FROM members m 
JOIN (
    SELECT user_id, SUM(totalworkyear) yearsjobscope 
    FROM members7 WHERE jobscope REGEXP 'Pharmacy' 
    GROUP BY user_id) m7 
    ON m.user_id = m7.user_id 
JOIN (
    SELECT user_id, SUM(totalworkyear_2) yearsskill 
    FROM members7_2 WHERE KnowledgeSkill REGEXP 'def' 
    GROUP BY user_id) m7_2 
    ON m.user_id = m7_2.user_id 

An SQLfiddle to test with。作爲最後說明，如果你的表變大，REGEX不是一個好辦法，你至少需要將分號分隔的值拆分成行，以便索引/精確匹配可以覆蓋它們。