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我有這樣的查詢:如何在postgresql查詢中選擇日期間隔?
select d.id from days as d JOIN tv_programs AS t ON (d.tv_program_id = t.id) WHERE d.date=? AND t.type=0 ORDER BY d.date, t.date DESC OFFSET 1;
則返回1個選擇日期(Date類型)的數據,但我想從STARTDATE至結束日期得到的值,例如,我想用一個查詢做哪些做這樣的事情:
select d.id from days as d JOIN tv_programs AS t ON (d.tv_program_id = t.id) WHERE d.date='2011-09-01' AND t.type=0 ORDER BY d.date, t.date DESC OFFSET 1;
select d.id from days as d JOIN tv_programs AS t ON (d.tv_program_id = t.id) WHERE d.date='2011-09-02' AND t.type=0 ORDER BY d.date, t.date DESC OFFSET 1;
select d.id from days as d JOIN tv_programs AS t ON (d.tv_program_id = t.id) WHERE d.date='2011-09-03' AND t.type=0 ORDER BY d.date, t.date DESC OFFSET 1;
這是可能的嗎?
是...... d.date是什麼類型? – Yahia
它是Date類型。 –