如何使用Python逐行匹配兩個純文本文件

Question

根據我的要求，我希望在Windows平臺上逐行匹配Python中的兩個文本文件。例如我有以下的文本文件：

文件1：

我叫XXX

命令成功完成。

我母親的名字是YYY

我的手機號碼是12345

的重型卡車撞向大樓在午夜

貨車吃在教師一個紅蘋果

文件2 ：

我的名稱是xxx

命令。成功。

我母親的名字是

它是什麼重型卡車撞向大樓

貨車在教師

我的不是足夠清楚，以便道歉吃一個蘋果我的問題是我如何可以對齊腳本電影與其字幕，我在Python中寫入以下代碼，但它不足以從兩個文本文件中獲得對齊：

# Open file for reading in text mode (default mode) 
f1 = open('F:/CONTRIBUTION 2017/SCRIPT-SUBTITLES CODES/Script Alignement Papers/f1.txt','r') 
f2 = open('F:/CONTRIBUTION 2017/SCRIPT-SUBTITLES CODES/Script Alignement Papers/f2.txt','r') 

#Print confirmation 
# print("-----------------------------------") 
#print("Comparing files ", " > " + fname1, " < " +fname2, sep='\n') 
# print("-----------------------------------") 

# Read the first line from the files 
f1_line = f1.readline() 
f2_line = f2.readline() 

# Initialize counter for line number 
line_no = 1 

# Loop if either file1 or file2 has not reached EOF 
while f1_line != '' or f2_line != '': 

    # Strip the leading whitespaces 
    f1_line = f1_line.rstrip() 
    f2_line = f2_line.rstrip() 

    # Compare the lines from both file 
    if f1_line != f2_line: 

     # If a line does not exist on file2 then mark the output with + sign 
     if f2_line == '' and f1_line != '': 
      print("=================================================================") 
      print("=================================================================") 
      print("line does not exist on File 2 ====================") 
      print("=================================================================") 
      print(">+", "Line-%d" % line_no, f1_line) 
     # otherwise output the line on file1 and mark it with > sign 
     elif f1_line != '': 

      print("=================================================================") 
      print("=================================================================") 
      print("otherwise output the line on file1 ====================") 
      print("=================================================================") 
      print(">", "Line-%d" % line_no, f1_line) 

     # If a line does not exist on file1 then mark the output with + sign 
     if f1_line == '' and f2_line != '': 
      print("=================================================================") 
      print("=================================================================") 
      print("=line does not exist on File 1 ====================") 
      print("=================================================================") 
      print("<+", "Line-%d" % line_no, f2_line) 
     # otherwise output the line on file2 and mark it with < sign 
     elif f2_line != '': 
      print("=================================================================") 
      print("=================================================================") 
      print("otherwise output the line on file2 ====================") 
      print("=================================================================") 
      print("<", "Line-%d" % line_no, f2_line) 

     # Print a blank line 
     print() 

    #Read the next line from the file 
    f1_line = f1.readline() 
    f2_line = f2.readline() 


    #Increment line counter 
    line_no += 1 

# Close the files 
f1.close() 
f2.close() 

如果有人能幫助做這個匹配，我會非常感激。

Answer 1

這將是很好的張貼您嘗試寫入的代碼。這感覺就像我們在做你的功課，讓你看起來很懶惰。話雖這麼說，看看下面的例子：

with open(file1, 'r') as f1, open(file2, 'r') as f2: 
    if f1.readlines() == f2.readlines(): 
     print('Files {} & {} are identical!'.format(file1, file2)) 

PS：這會檢查文件是否相同。如果你想要一個邏輯比較的東西，你必須先做一些研究。

Answer 2

一種可能的方法是將文件的行存儲在列表中，然後比較列表。

lines_of_file1 = [] 
file = open("file1.txt","r") 
line = 'sample' 
while line != '': 
    line = file.readline() 
    lines_of_file1.append(line) 
file.close() 
lines_of_file2 = [] 
file = open("file2.txt","r") 
line = 'sample' 
while line != '': 
    line = file.readline() 
    lines_of_file2.append(line) 
file.close() 
same = True 
for line1 in lines_of_file1: 
    for line2 in lines_of_file2: 
     if line1 != line2: 
      same = False 
      break 
if same: 
    print("Files are same") 
else: 
    print("Files are not same") 

希望有幫助。