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我一直在努力與我的程序。我必須爲線性方程創建一個對象類。然後我必須有一個測試程序來獲得x和y值。沒有什麼是強調,並在我的書看例子,我只是沒有看到我要去哪裏錯了。有人可以幫我弄清楚如何解決它?我的結果出來爲:如何讓我的對象類正常工作?
「方程無解
方程無解
X是NaN和y爲NaN」
我的對象類是:
private double a, b, c, d, e, f;
private double x, y;
public LinearEquation() {
}
LinearEquation(double a, double b, double c, double d, double e, double f) {
}
public boolean isSolvable() {
if (((a * d) - (b * c)) == 0) {
System.out.println("The equation has no solution");
return false;
}
return true;
}
public double getX() {
if (isSolvable());
x = (((e * d) - (b * f))/((a * d) - (b * c)));
return x;
}
public double getY() {
if (isSolvable());
y = (((a * f) - (e * c))/((a * d) - (b * c)));
return y; }
我的測試類是:
public static void main(String[] args) {
double a = 9.0;
double b = 4.0;
double c = 3.0;
double d = -5.0;
double e = -6.0;
double f = -21.0;
LinearEquation numberSet = new LinearEquation(a, b, c, d, e, f);
double xValue = numberSet.getX();
double yValue = numberSet.getY();
System.out.println("x is " + xValue + " and y is " + yValue); }
這是你的意思嗎? public LinearEquation(double a,double b,double c,double d,double e,double f){ \t} 我試過了,但仍得到相同的結果。 –
是的。嘗試'public LinearEquation(double a,double b,double c,double d,double e,double f){this.a = a; this.b = b; this.c = c; this.d = d;這e = e; this.f = f; }' – Amadan
它的工作!謝謝! –