用於生成以下輸出的SQL查詢

顯示用戶標識，用戶名，總金額，折扣後要支付的金額並將別名命名爲User_ID，user_name，Total_amount和Paid_amount。按用戶ID降序顯示記錄。點擊TABLE SHCEMA獲取表格用於生成以下輸出的SQL查詢

這是我寫的代碼。但是，這是不是顯示了預期的結果：

SELECT 
    USERS.USER_ID AS User_ID, 
    NAME AS user_name, 
    (FARE * NO_SEATS) AS Total_amount 
FROM 
    USERS 
INNER JOIN 
    TICKETS ON USERS.USER_ID = TICKETS.USER_ID 
INNER JOIN 
    PAYMENTS ON TICKETS.TICKET_ID = PAYMENTS.TICKET_ID 
INNER JOIN 
    DISCOUNTS ON PAYMENTS.DISCOUNT_ID = DISCOUNTS.DISCOUNT_ID 
GROUP BY 
    USERS.USER_ID, NAME, FARE, NO_SEATS 
ORDER BY 
    USERS.USER_ID DESC;

這是預期的輸出：

USER_ID USER_NAME TOTAL_AMOUNT PAID_AMOUNT 
---------------------------------------------- 
5  Krena   700   625 
4  Johan   800   775 
3  Ivan   3000  2900 
1  John   4000  3950 
1  John   4000  3950 
1  John   2000  1900

來源

2017-07-16 Niko Namikaze

您正在使用哪個[DBMS]（https://en.wikipedia.org/wiki/Database）？ Postgres的？甲骨文？ DB2？火鳥？ –

這將工作，嘗試

SELECT 
USERS.USER_ID AS USER_ID, 
USERS.NAME AS USER_NAME, 
(TICKETS.FARE * TICKETS.NO_SEATS) AS TOTAL_AMOUNT, 
(TICKETS.FARE * TICKETS.NO_SEATS - DISCOUNTS.DISCOUNT_AMOUNT) AS PAID_AMOUNT 
FROM 
USERS 
INNER JOIN TICKETS 
     ON USERS.USER_ID=TICKETS.USER_ID 
INNER JOIN PAYMENTS 
     ON TICKETS.TICKET_ID=PAYMENTS.TICKET_ID 
INNER JOIN DISCOUNTS 
     ON PAYMENTS.DISCOUNT_ID=DISCOUNTS.DISCOUNT_ID 
ORDER BY USERS.USER_ID DESC;

來源

2017-07-16 17:46:34

謝謝伴侶。這無效地工作 –

試試這個代碼。

SELECT 
USERS.USER_ID AS USER_ID, 
USERS.NAME AS USER_NAME, 
(TICKETS.FARE * TICKETS.NO_SEATS) AS TOTAL_AMOUNT, 
(TICKETS.FARE * DISCOUNTS.DISCOUNT_AMOUNT) + TICKETS.FARE AS PAID_AMOUNT 
FROM 
USERS USERS 
INNER JOIN TICKETS TICKETS 
     ON USERS.USER_ID=TICKETS.USER_ID 
INNER JOIN PAYMENTS PAYMENTS 
     ON TICKETS.TICKET_ID=PAYMENTS.TICKET_ID 
INNER JOIN DISCOUNTS DISCOUNTS 
     ON PAYMENTS.DISCOUNT_ID=DISCOUNTS.DISCOUNT_ID 
ORDER BY USERS.USER_ID DESC;

我很困惑你的數據庫結構，如果它爲什麼是數字數據類型？您可能想要將其更改爲十進制，如果您需要並將其長度設爲（11,2），因爲我假設您的折扣表中的折扣金額以百分比爲準？或者在這裏粘貼你的示例數據庫，這樣我就可以更新我的代碼。

來源

2017-07-16 17:11:39

折扣的金額不在百分比，我得到的前三列除了最後一個精確的輸出。折扣列的確切代碼是什麼？ @ G.Panga –

如果您只是從FARE中扣除折扣，請務必將「（TICKETS.FARE * DISCOUNTS.DISCOUNT_AMOUNT）+ TICKETS.FARE作爲PAID_AMOUNT」更改爲「（DISCOUNTS.DISCOUNT_AMOUNT - TICKETS.FARE）作爲PAID_AMOUNT」 –

如果我有足夠的聲望，我會寫這個評論（嘆氣）：你還沒有完全定義你的預期結果是什麼。

我假設如下：

打印的總金額爲用戶，無論是TOTAL_AMOUNT（即官方價格），Paid_amount（即折扣後），因此這將包括所有的門票和他們的付款。
我假設的折扣是從公平的扣除正數，每1座

那麼這應該做的伎倆：

SELECT 
    USER_ID AS USER_ID, 
    NAME AS USER_NAME, 
    sum(FARE * NO_SEATS) AS TOTAL_AMOUNT, 
    sum((FARE - DISCOUNT_AMOUNT) * NO_SEATS) AS PAID_AMOUNT 
FROM USERS u 
INNER JOIN TICKETS t 
     ON u.USER_ID=t.USER_ID 
INNER JOIN PAYMENTS p 
     ON t.TICKET_ID=p.TICKET_ID 
INNER JOIN DISCOUNTS d 
     ON p.DISCOUNT_ID=d.DISCOUNT_ID 
group by USER_ID, name 
ORDER BY USER_ID DESC;

來源

2017-07-16 17:31:43 elonderin

用於生成以下輸出的SQL查詢

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