如果我有一個形狀像這樣的Python列表:重塑一個Python列表,同時保持順序
T = [
['07,07,2012 22:10', ['people','drama','melody','bun']],
['08,07,2012 21:04', ['queen','group']],
['08,07,2012 21:23', ['printing','market','shopping']],
['08,07,2012 21:04', ['people','bun']],
['08,11,2012 11:14', ['kangaroo']]
]
我需要的是這個列表轉換成這種格式:
T =[
['07,07,2012 22:10', 'people'],
['07,07,2012 22:10', 'drama'],
['07,07,2012 22:10', 'melody'],
['07,07,2012 22:10', 'bun'],
['08,07,2012 21:04', 'queen'],
['08,07,2012 21:04', 'group'],
['08,07,2012 21:23', 'printing'],
['08,07,2012 21:23', 'market'],
['08,07,2012 21:23', 'shopping'],
['08,07,2012 21:04', 'people'],
['08,07,2012 21:04', 'bun'],
[''08,11,2012 11:14'', 'kangaroo']
]
即對於第一個子元素的長度大於1(在原始列表T中)的每個元素,分割第一個子元素(a[1] for a in T if len(a[1] > 1)
)並將其作爲具有相同時間戳的另一個列表追加。也許我的話缺乏解釋,但上述樣本無疑解釋了我需要做的事情。任何幫助,將不勝感激。
或者使用一個列表而不是一個元組來獲得OP所要求的內容(儘管應該不重要)。 –
謝謝@ flornquake..you藝術家總結了這一切。非常感謝 :-) – khan