獲取在PHP

Question

兩個字符之間的字符串我在PHP中的字符串說

$string = 'All I want to say is that <#they dont really care#> about us. 
    I am wasted away <#I made a million mistake#>, am I too late. 
    Theres a storm in my head and a race on my bed, <#when you are not near#>' ; 


$expected_output = array(
    'they dont really care', 
    'I made a million mistake', 
    'when you are not near' 
); 

我怎樣才能達致這使用PHP正則表達式？ 感謝您的閱讀:)

Answer 1

一個更緊湊的版本：

$regex = '~<#\K.*?(?=#>)~'; 
preg_match_all($regex, $string, $matches); 
print_r($matches[0]); 

看到比賽中the regex demo。

匹配

they dont really care 
I made a million mistake 
when you are not near 

說明

• 的^錨斷言，我們是在字符串
• <#開頭的左定界符
• 的匹配告訴發動機放棄迄今爲止與最終比賽匹配的東西，它返回
• .*?懶洋洋地匹配chars直到點...
• 先行(?=#>)可以斷言，接下來是#>
• 的$錨斷言，我們是在字符串

結束參考

• Lookahead and Lookbehind Zero-Length Assertions
• Mastering Lookahead and Lookbehind

Answer 2

你可以使用這個表達式：

在

'/<#(.*?)#>/s' 

preg_match_all函數調用。

我不想給你完整的代碼，但這應該足以讓你去。

Answer 3

此代碼將做你想做的

<?php 

$string = 'All I want to say is that <#they dont really care#> about us. 
    I am wasted away <#I made a million mistake#>, am I too late. 
    Theres a storm in my head and a race on my bed, <#when you are not near#>' ; 


preg_match_all('/<#(.*)#>/isU', $string, $matches); 

var_dump($matches[1]); 

Answer 4

通過前瞻和回顧後，

(?<=<#).*?(?=#>) 

最後調用函數preg_match_all打印匹配的字符串。

你PHP代碼會，

<?php 
$data = 'All I want to say is that <#they dont really care#> about us. 
    I am wasted away <#I made a million mistake#>, am I too late. 
    Theres a storm in my head and a race on my bed, <#when you are not near#>' ; 
$regex = '~(?<=<#).*?(?=#>)~'; 
preg_match_all($regex, $data, $matches); 
var_dump($matches); 
?> 

輸出：

array(1) { 
    [0]=> 
    array(3) { 
    [0]=> 
    string(21) "they dont really care" 
    [1]=> 
    string(24) "I made a million mistake" 
    [2]=> 
    string(21) "when you are not near" 
    } 
}