重複PHP代碼或腳本

Question

簡單的問題，在Java中，有Timer類，或AlarmManager，甚至一段時間（true）循環來重複某些代碼，我如何實現與PHP代碼，我想重複一些PHP代碼/腳本，我曾嘗試：

while(true){ 
////Give me an Error , 'No Data Received from WebSite/Not Response 
} 

function Check(){ 
////Do Code 
Check() 
////Syntax and Others Error , does Not Work 
} 

echo "<script>setTimeout('check()',10);"; ////does not Work too 


Additional Code : 

$q=mysql_query("SELECT message FROM $tbl_name WHERE pass='".$_SESSION['Logged']."'"); 
while($row = mysql_fetch_array($q)){ 
while(true) 
echo $row['message']; ///In French Language saying that the server closed the connection without sending any  Data, 
Error : Erreur 324 (net::ERR_EMPTY_RESPONSE) : Le serveur a mis fin à la connexion sans envoyer de données. 

} 

Answer 1

不能得到你想要做什麼，但作爲我明白你的問題，你 可以使用類似：

while ($something == true) 
{ 
//code to process here and keeps repeating until condition is met. 
myFunction(); 

} 

function myFunction(){ 
//code of your function 
}