將數值從一種方法返回到另一種方法

Question

/* Assume as precondition that the list of players is not empty. 
* Returns the winning score, that is, the lowest total score. 
* @return winning score 
*/ 
public int winningScore() { 
    Player thePlayer = players.get(0); 
    int result = thePlayer.totalScore(); 
    for (int i = 0; i < players.size(); i++){ 
     int p = players.get(i).totalScore(); 
     if (p < result) { 
      result = players.get(i).totalScore(); 
     } 
    } 
    return result; 
} 

/* Returns the list of winners, that is, the names of those players 
* with the lowest total score. 
* The winners' names should be stored in the same order as they occur 
* in the tournament list. 
* If there are no players, return empty list. 
* @return list of winners' names 
*/ 
public ArrayList<String> winners() { 
    ArrayList<String> result = new ArrayList<String>(); 

    for (int i = 0; i < players.size(); i++) 
     if (!players.isEmpty()) 
      return result; 
} 

因爲它在註釋中聲明，所以我試圖在winners方法中返回winningScore（）結果，以便返回贏家/贏家名稱。

我設法只返回所有的獲獎者，但是如果它應該從winningScore（）方法調用或者不是有點困惑？

我明白我當前的代碼是不正確的贏家

在正確的方向推任何/提示，將不勝感激！謝謝！

Answer 1

你想要做的就是在你的獲勝者方法中找到所有獲勝分數的選手對象。

• 要做到這一點，您需要首先通過致電 您的winningScore方法來計算獲勝分數。
• 接下來，您會發現所有玩家對象的totalScore等於以前計算的獲勝分數 。你想要返回這些。

然後爲獲獎者的方法生成的代碼應該是這樣的：

public ArrayList<String> winners() { 
    ArrayList<String> result = new ArrayList<String>(); 

    int winningScore = winningScore(); 

    for (int i = 0; i < players.size(); i++) 
     if (players.get(i).totalScore() == winningScore) 
      result.add(players.get(i).getName()) 

    return result; 
} 

如果要簡化代碼，你可以通過循環使用ArrayList迭代器這樣的替代for循環，因爲你不使用索引變量i：

for (Player player : players) { 
    if (player.totalScore() == winningScore) 
     result.add(player.getName()) 
}