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我有一個查詢在MS Access中保存並直接從ms訪問啓動時工作。在PHP中的MS Access查詢返回沒有結果
我創建了一個php頁面,通過調用該查詢的名稱輸出該信息,但查詢不返回任何內容! 我的代碼應該可以工作,因爲在我調用的Access中有其他查詢,並且它們返回數據。
- 查詢工作類型和PHP執行時的訪問
- 查詢不返回結果展開(雙擊)時
"SELECT * see query below"
- 查詢時由MS接入的名字從PHP
"SELECT * FROM Query1"
稱爲不返回結果 - 在同一數據庫中的其他查詢時,通過MS接入的名字從PHP
"SELECT * FROM Query2"
稱爲按預期執行
SELECT *
FROM (SELECT a2.[vendor_oel_yr],
Count(a2.qty) AS eol_qty
FROM (SELECT "wintel" AS Platform,
s.city & "," & s.state AS
[Physical Location],
"" AS
[Special Flag (Project)],
"" AS
[Special Flag (sub location)],
"" AS
[location Floor],
"" AS
[Room Discriptor],
Format(s.unitprce, "currency") AS [Unit Price],
"hp" AS Manufacturer,
t.make_model AS Model,
s.itemnmbr AS [Part Number],
s.qty AS Qty,
s.itemdesc AS Description,
s.sn AS [Serial Number]
,
""
AS [Asset Tag #],
"" AS Environment,
t.computer AS
[Device Name (Naming Standard)],
s.docdate AS [Install Date],
4 AS
[Vendor Useful Life],
"" AS
[Operational Useful Life],
s.docdate + (4 * 365) AS
[Vendor EOL Date],
"" AS
[Operational EOL Date]
,
Format(s.qty * s.unitprce, "currency") AS
[Purchase Price],
Year(s.docdate + (4 * 365)) AS Vendor_OEL_Yr
FROM sayers_invoice AS s
INNER JOIN tamit_wintel AS t
ON s.sn = t.serial_number
WHERE Len(s.sn) > 0) AS a2
GROUP BY a2.[vendor_oel_yr]) AS a2O;
做了什麼調試?檢查數據庫調用在PHP中的返回值? –
我有多個調用多個查詢(同一個數據庫)。他們都從PHP工作。唯一的例外是這個查詢 - 它在MS Access中調用時起作用 – Andrew
您是否嘗試過直接對訪問執行結果查詢? – Babblo