根據表格數據查找每個部門的第三最大工資

Question

我需要找出table中每個部門的員工的3rd maximum salary。如果不存在3rd maximum salary則顯示2nd maximum salary。如果沒有2nd maximum salary存在，那麼找到highest salary。如何在sql-server中實現這個結果？

的table結構如下

create table employee1(empid int, empname varchar(10), deptid int, salary money) 

insert into employee1 
select 1,'a',1, 1000 
union 
select 1,'b',1, 1200 
union 
select 1,'c',1, 1500 
union 
select 1,'c',1, 15700 
union 
select 1,'d',2, 1000 
union 
select 1,'e',2, 1200 
union 
select 1,'g',3, 1500 

我試圖獲得最大的薪水爲每個類別使用row_number功能的常見方式給出。

;with cte 
as 
( 
select ROW_NUMBER() over(partition by deptid order by salary) as id, * from employee1 
) 
select * from cte 

Answer 1

Select EmpID,empname,deptid,salary 
From (
Select * 
     ,RN = Row_Number() over (Partition By deptid Order By Salary) 
     ,Cnt = sum(1) over (Partition By deptid) 
From employee1 
    ) A 
Where RN = case when Cnt<3 then Cnt else 3 end 

返回

Answer 2

答案取決於您是否想要關係以及如何處理它們。如果你不需要任何聯繫，即使一個員工與另一個員工聯繫，它也會成爲下一個最高薪水，那麼訣竅就是使用row_number，就像你在薪水中下降時顯示的那樣，然後使用另一個row_number來反轉它。如果你不想使用row_number第二次你可以用一些其他的技術做得一樣好，但第1步是找到最高的第2步是扭轉這種秩序

; WITH cteRankSalariesByDepartment AS (
    SELECT 
     * 
     ,RowNum = DENSE_RANK() OVER (PARTITION BY deptid ORDER BY salary DESC) 
    FROM 
     employee1 
) 

, cteReverseRankHighestSalaries AS (
    SELECT 
     * 
     ,RowNum2 = DENSE_RANK() OVER (PARTITION BY deptid ORDER BY RowNum DESC) 
    FROM 
     cteRankSalariesByDepartment 
    WHERE 
     RowNum <= 3 
) 

SELECT * 
FROM 
    cteReverseRankHighestSalaries 
WHERE 
    RowNum2 = 1 

根據您的意見更新DENSE_RANK()你可以只需使用它代替row_number()，您將獲得您的關係。

Answer 3

你可以嘗試查詢象下面這樣：

select * from 
(
select 
empid, 
empname , 
deptid , 
salary , 
ROW_NUMBER() over(partition by deptid order by id desc) as rev_id 
from 
( 
select 
ROW_NUMBER() over(partition by deptid order by salary) as id, 
empid, 
empname , 
deptid , 
salary 
from employee1 
) 
t where id<=3 
)t where rev_id=1 

working demo

Answer 4

你可以使用UNION

;with cte 
as 
( 
select ROW_NUMBER() over(partition by deptid order by salary) as id, * from employee1 
) 

--get the 3rd highest 
select 
    * 
from cte 
where id = 3 

union 

--get the highest/max 
select 
    c.* 
from cte c 
--this determines the highest which salary for each dept 
inner join 
    (select deptid, max(id) id 
    from cte 
    group by deptid) x on x.deptid = c.deptid and x.id = c.id 
--this limits it on depts that aren't in the list in the first part of the query 
where 
    c.deptid not in (select deptid from cte where id = 3) 

Answer 5

只要你查詢的需求數與條件ROW_NUMBER如下：

;with cte 
as 
( 
select ROW_NUMBER() over(partition by deptid order by salary desc) as id, 
    Cnt = count(*) over(partition by deptid), * from employee1 
) 
select * from cte where (cnt >= 3 and id = 3) 
or (cnt < 3 and id = 1) 

Answer 6

要增加你的問題我加了兩個員工，在第三位置同樣的薪水。

爲了得到這個，你需要第一個dense_rank部門的工資。後，您需要倒L的工資等級和獲取位置1

嘗試

DECLARE @employee1 TABLE 
     ( 
     empid INT, 
     empname VARCHAR(10), 
     deptid INT, 
     salary MONEY 
    ) 

    INSERT @employee1 Values 
    (1,'a',1, 1000 ) 
,(1,'b',1, 1200) 
,(2,'bb',1, 1200) 
,(1,'c',1, 1500) 
,(3,'ccc',1, 1500) 
,(1,'c',1, 15700) 
,(1,'d',2, 1000) 
,(1,'e',2, 1200) 
,(1,'g',3, 1500) 

    WITH cte_rank 
     AS (SELECT Dense_rank() 
         OVER ( 
         partition BY deptid 
         ORDER BY salary) SalaryRank, 
        * 
      FROM @employee1), 
     cte_final 
     AS (SELECT Dense_rank() 
         OVER ( 
         partition BY deptid 
         ORDER BY salaryrank DESC) SalaryRankReverse, 
        * 
      FROM cte_rank 
      WHERE salaryrank <= 3) 
    SELECT * 
    FROM cte_final 
    WHERE salaryrankreverse = 1 

結果

SalaryRankReverse SalaryRank   empid  empname deptid  salary 
-------------------- -------------------- ----------- ---------- ----------- --------------------- 
1     3     1   c   1   1500.00 
1     3     3   ccc  1   1500.00 
1     2     1   e   2   1200.00 
1     1     1   g   3   1500.00