與其中2個表

Question

條款我有2個MySQL表像在下面的例子中選擇MySQL數據：

CARS

Id  CAR NAME   AGE 

1 Ford  2 years 
2 AUDI  1 years 
3 Ford  2 years 

OPTIONS

Id id_car option 

1 1  ESP 
2 2   ABS 
3 3   ABS 
4 3   ESP 

，我需要選擇所有2歲的汽車有ABS和ESP。 所以應該在這個例子返回：3福特

如果你有什麼想法？

感謝

Answer 1

您需要使用上的選項表的連接：

SELECT c.* FROM CARS c 
JOIN OPTIONS o ON o.id_car=c.id AND o.option='ABS' 
JOIN OPTIONS o2 ON o2.id_car=c.id AND o2.option='ESP' 
WHERE c.age >= 2 

或子查詢：

SELECT c.* FROM CARS c 
WHERE c.age >= 2 
AND c.id IN (SELECT o.id_car FROM OPTIONS o WHERE o.id_car=c.id AND o.option='ABS') 
AND c.id IN (SELECT o.id_car FROM OPTIONS o WHERE o.id_car=c.id AND o.option='ESP') 

Answer 2

SELECT * FROM CARS LEFT JOIN `OPTIONS` ON `OPTIONS`.`id_car` = `CARS`.`id` WHERE `OPTIONS`.`option` LIKE '%ABS%' 

會做ABS，如果你想要更多，你必須有PHP寫的每個選項的SQL增加使你的最終結果將是

SELECT * FROM CARS LEFT JOIN `OPTIONS` ON `OPTIONS`.`id_car` = `CARS`.`id` WHERE (`OPTIONS`.`option` LIKE '%ABS%' OR `OPTIONS`.`option` LIKE '%ESP%') 

Answer 3

我建議你改變「年齡」一欄，要麼「DATE_CREATED」，或者只是將它作爲年齡並僅使用整數。

如果你作爲一個整數使用，只是這樣做：

SELECT c.id, c.car 
    FROM cars c 
    INNER JOIN options o 
    ON o.id_car = c.id 
    WHERE c.age >= 2 

Answer 4

本集團/有將確保該車既具有所期望的功能。

select c.id, c.name 
    from cars c 
     inner join options o 
      on c.id = o.id_car 
       and o.option in ('ABS','ESP') 
    where c.age = 2 
    group by c.id, c.name 
    having count(distinct o.option) = 2 

Answer 5

SELECT * FROM CARS WHERE id IN 
(SELECT id_car FROM OPTIONS WHERE GROUP_CONCAT(option) ='ABS,ESP' 
GROUP BY id_car) 
WHERE age ='2 years' GROUP BY CARS.name 

Answer 6

我也試過這種方式，並返回我都福特1和3 ....

的我只想要3福特與ABS和ESP

Answer 7

試試吧::

Select new_car.name 
    From (select * from cars where year=2) as new_car 
    inner join option as op 
    on (op.id_car = new_car.id AND (op.option = `ABS` OR op.option = `ESP`)) 

:)