如何統計所有結果和計數具體在同一個查詢 - MySql

Question

我需要統計所有FirstExtracted爲特定的日期，我需要統計所有LastExtracted爲同一日期。所以，今天，我需要所有FirstExtracted和LastExtracted等於2012-10-24。

這是我到目前爲止，但它沒有帶來LastExtracted。它輸出LastExtracted的數量相同FirstExtracted：

(SELECT LastExtracted,FirstExtracted, 
COUNT(FirstExtracted) AS FirstCount, 
COUNT(LastExtracted) AS LastCount, 
DATE_FORMAT(`LastExtracted`,'%Y-%m-%d') AS Lastdate, 
DATE_FORMAT(`FirstExtracted`,'%Y-%m-%d') AS Firstdate 
FROM results 
WHERE DATE_FORMAT(`FirstExtracted`,'%Y-%m-%d') = DATE_FORMAT(`LastExtracted`,'%Y-%m-%d')) 
UNION ALL 
(SELECT LastExtracted,FirstExtracted, 
COUNT(FirstExtracted) AS FirstCount, 
COUNT(LastExtracted) AS LastCount, 
DATE_FORMAT(`LastExtracted`,'%Y-%m-%d') AS Lastdate, 
DATE_FORMAT(`FirstExtracted`,'%Y-%m-%d') AS Firstdate 
FROM results 
WHERE DATE_FORMAT(`FirstExtracted`,'%Y-%m-%d') = DATE_FORMAT(`LastExtracted`,'%Y-%m-%d') GROUP BY Firstdate) 
ORDER BY Firstdate DESC 
LIMIT 20 

也許我應該使用內部聯接？

更新： 所以使用您的查詢，我做了一些更改，使它現在爲我做了別的事情。如果你看一下這個頁面我把查詢了

semesterold.com/code2.html

我想指望由藝術家所有標題和組。這將是一個數組。那麼我希望子查詢通過匹配藝術家的searchtype進行計數。所以如果db有akon，rihanna，chris brown。我希望它能夠統計出每個藝術家有多少個標題，比如說akon有100個。然後我想要顯示標題數量，然後統計這100個標題中有多少是Google，bing，特定於akon的站點等。

Answer 1

我會使用union得到兩個結果（FirstExtracted和LastExtracted）分開，然後使用子查詢合併。

SELECT 
    sub.date, sum(sub.FirstCount) AS FirstCount, 
    sum(sub.LastCount) AS LastCount 
    FROM (
     SELECT 
      DATE_FORMAT(`FirstExtracted`,'%Y-%m-%d') AS date, 
      COUNT(FirstExtracted) AS FirstCount, 0 AS LastCount 
     FROM results 
     GROUP BY date 
     UNION ALL 
     SELECT 
      DATE_FORMAT(`LastExtracted`,'%Y-%m-%d'), 
      0, COUNT(LastExtracted) 
      FROM results 
      GROUP BY date 
    ) AS sub 
    GROUP BY sub.date 

說你今天萃取今日最近提取第一時間和292 220項。其中用於其它日期的條目，這將給你：

+------------+------------+-----------+ 
| date  | FirstCount | LastCount | 
+------------+------------+-----------+ 
| 2012-10-24 |  220 |  292 | 
+------------+------------+-----------+ 

更新單獨的UNION會給你下面的結果。注意零佔位符。

+------------+------------+-----------+ 
| date  | FirstCount | LastCount | 
+------------+------------+-----------+ 
| 2012-10-24 |  220 |   0 | 
+------------+------------+-----------+ 
| 2012-10-24 |   0 |  292 | 
+------------+------------+-----------+ 

Answer 2

我建議在查詢中添加DISTINCT：

(SELECT LastExtracted,FirstExtracted, 
COUNT(DISTINCT FirstExtracted) AS FirstCount, 
COUNT(DISTINCT LastExtracted) AS LastCount, 
DATE_FORMAT(`LastExtracted`,'%Y-%m-%d') AS Lastdate, 
DATE_FORMAT(`FirstExtracted`,'%Y-%m-%d') AS Firstdate 
FROM results 
WHERE DATE_FORMAT(`FirstExtracted`,'%Y-%m-%d') = DATE_FORMAT(`LastExtracted`,'%Y-%m-%d')) 
UNION ALL 
(SELECT LastExtracted,FirstExtracted, 
COUNT(DISTINCT FirstExtracted) AS FirstCount, 
COUNT(DISTINCT LastExtracted) AS LastCount, 
DATE_FORMAT(`LastExtracted`,'%Y-%m-%d') AS Lastdate, 
DATE_FORMAT(`FirstExtracted`,'%Y-%m-%d') AS Firstdate 
FROM results 
WHERE DATE_FORMAT(`FirstExtracted`,'%Y-%m-%d') = DATE_FORMAT(`LastExtracted`,'%Y-%m-%d') GROUP BY Firstdate) 
ORDER BY Firstdate DESC 
LIMIT 20