計數和具有查詢

Question

請查看下錶：

Id Code  Name  State  District  Status 
----------------------------------------------------------- 
1  10001 ABC  Gujarat  Jamnagar  1 
2  10002 BCA  Gujarat  Amreli   0 
3  10003 XYZ  NJ   ACX   1 
4  10001 VBC  Gujarat  Jamnagar  1 

我有查詢下面

SELECT STATE, 
    District, 
    SUM(CASE 
      WHEN STATUS = 0 
       THEN 1 
      ELSE 0 
      END) Active, 
    SUM(CASE 
      WHEN STATUS = 1 
       THEN 1 
      ELSE 0 
      END) InActive 
FROM TableA 
GROUP BY STATE, 
    District 

現在它將會返回下面的結果對我來說

State District Active InActive 
------------------------------------ 
Gujarat Jamnagar 0  2 
Gujarat Amreli  1  0 
NJ  ACX  0  1 

但我需要算單行，其Code是相同的，所以它將返回InActive作爲1的 StateGujarat和DistrictJamnagar不是2.

我該如何做到這一點？

Answer 1

你如何明確地選擇子查詢中的所有列？

SELECT STATE, 
    District, 
    SUM(CASE 
      WHEN STATUS = 0 
       THEN 1 
      ELSE 0 
      END) Active, 
    SUM(CASE 
      WHEN STATUS = 1 
       THEN 1 
      ELSE 0 
      END) InActive 
FROM (
    SELECT DISTINCT STATE, 
     District, 
     STATUS 
    FROM tableA 
    ) a 
GROUP BY STATE, 
    District 

SQLFiddle Demo

Answer 2

Rater than SUM，select MAX，所以這些值不會聚合。