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當我試圖從顯示警告的數據庫中提取數據錯誤警告:mysqli_affected_rows()期望參數1是第二行的C: xampp htdocs ajax-complete live-table-post.php中的mysqli,布爾值
警告:mysqli_affected_rows()預計參數1是mysqli的,在C給定的boolean:\ XAMPP \ htdocs中\ Ajax的完整\上線實況表post.php中23
我我試圖從數據庫中獲取數據它顯示錯誤我也用musqli_affedted_rows而不是mysqli_num_rows但它顯示相同的錯誤
<?php
$host = "localhost"; $username = "root"; $password = "";$db_name = "ajax_complete";
$conn = mysqli_connect($host, $username, $password, $db_name) or die("cannot connect");
$output = '';
$sql = "SELECT * FROM tbl_live-crud ORDER BY id DESC";
$result = mysqli_query($conn,$sql);
$output.= '
<div class="table-responsive">
<table class="table table-bordered">
<tr>
<td width="10%;"></td>
<td width="20%;"></td>
<td width="20%;"></td>
<td width="20%;"></td>
<td width="10%;"></td>
</tr>';
if(mysqli_num_rows($result) > 0){
while($row = mysqli_fetch_array($result)){
$output .= '
<td>'.$row['id'].'</td>
<td class="fname" data-id1="'.$row['id'].'" contenteditable>'.$row['fname'].'</td>
<td class="lname" data-id2="'.$row['id'].'" contenteditable>'.$row['lname'].'</td>
<td class="email" data-id3="'.$row['id'].'" contenteditable>'.$row['email'].'</td>
<td><button name="delete" id="delete" data-id4="'.$row['id'].'">X</button></td>';
}
$output = '
<tr>
<td id="fname" contenteditable></td>
<td id="lname" contenteditable></td>
<td id="email" contenteditable></td>
<td id="btn_add" name="btn_add" class="btn btn-xs btn-success"><button>+</button></td>
</tr>';
}else{
$output = '
<tr>
<td colaspan="4"> Data not Found</td>
</tr>';
}
$output .='</table>
</div>';
?>
兩個代碼不工作 –
來源:http://www.w3schools.com/php/php_mysql_select.asp –
注意:試圖讓非對象的屬性在C:\ XAMPP \ htdocs中\ ajax-完成\ live-table-post.php 26行 –