當我println時，Char不會添加到我的字符串中？

Question

我正在製作一個方法presentParticiple，返回一個單詞EnglishWord的現在分詞。

當我運行程序並且英語字符以輔音結尾時（第2個if語句），我聲明的字符不會被添加。我做錯了什麼？

private String ending1 = ".*[b,c,d,f,g,h,j,k,l,m,n,p,q,r,s,t,v,w,x,y,z]e"; 
private String consonant = ".*[b,c,d,f,g,h,j,k,l,m,n,p,q,r,s,t,v,w,x,y,z]"; 

public void run() { 
    presentParticiple("jam");   
} 

private String presentParticiple(String EnglishWord) { 
    String correctWord = ""; 
    if (EnglishWord.endsWith(ending1)) { 
     correctWord = EnglishWord.substring(0,EnglishWord.length()-1)+"ing"; 
    } 

    else if (EnglishWord.endsWith(consonant)) { 
     char ch = EnglishWord.charAt(EnglishWord.length()); 
     correctWord = EnglishWord.substring(0, EnglishWord.length())+ch+"ing"; 


    } else { 
     correctWord = EnglishWord+"ing"; 
    } 
    println(correctWord); 
    return correctWord; 
} 

Answer 1

以下是一些可行的代碼（包含上述建議）。

public class EnglishTest 
{ 
    public static void main (String[] args) 
    { 
    String[] words = { "jam", "rue", "raze", "knock", "need" }; 
    for (String word : words) 
     presentParticiple (word); 
    } 

    private static final String ending1 = ".*[b-df-hj-np-tv-z]e"; 
    private static final String consonant = ".*[b-df-hj-np-tv-z]"; 

    private static String presentParticiple (String englishWord) 
    { 
    String correctWord = ""; 
    if (englishWord.matches (ending1)) 
     correctWord = englishWord.substring (0, englishWord.length() - 1) + "ing"; 
    else if (englishWord.matches (consonant)) 
    { 
     char ch = englishWord.charAt (englishWord.length() - 1); 
     correctWord = englishWord + ch + "ing"; 
    } 
    else 
     correctWord = englishWord + "ing"; 

    System.out.println (correctWord); 
    return correctWord; 
    } 
} 

雖然你的算法有問題。例如嘗試'敲'。