的Java：轉換StreamResult到DOM

Question

我執行從一個XML格式的XSLT轉換到另一個撒克遜和XSLT，以後有什麼轉變的結果XML轉換成Java的DOM與它進一步的工作：

System.setProperty("javax.xml.transform.TransformerFactory", "net.sf.saxon.TransformerFactoryImpl"); 
TransformerFactory tFactory = TransformerFactory.newInstance(); 

Transformer transformer = tFactory.newTransformer(new StreamSource(new File("xslt.xsl"))); 
transformer.transform(new StreamSource(new File(inputXML)), 
            new StreamResult(new File (outputXML))); 

DocumentBuilder documentBuilder = DocumentBuilderFactory.newInstance().newDocumentBuilder(); 
Document document = documentBuilder.parse(outputXML); 

我不喜歡在這種情況下，正在創建中間文件outputXML。是否有可能避免其創建？

Answer 1

DocumentResult result = new DocumentResult（）; （新的StreamSource（new File（inputXML）），result）;

Document transformedDoc = result.getDocument（）;

Answer 2

答案由@Andreas提供。如果有人有興趣，在我的情況下，結果代碼片段是這樣的：

System.setProperty("javax.xml.transform.TransformerFactory", "net.sf.saxon.TransformerFactoryImpl"); 
TransformerFactory tFactory = TransformerFactory.newInstance(); 

DOMResult xmlResult = new DOMResult(); 
Transformer transformer = tFactory.newTransformer(new StreamSource(new File("xslt.xsl"))); 
     transformer.transform(new StreamSource(new File(outputXML)), 
           xmlResult); 

Document document = (Document) xmlResult.getNode();