在SQL

在計算行使用金額

我有這樣的代碼，運行時應該返回出租車酒店和食品總數的計數：在SQL

SELECT 
    COUNT(CASE WHEN [TaxiHotelFood] LIKE '%Taxi%' THEN 1 END) AS "Taxis", 
    COUNT(CASE WHEN [TaxiHotelFood] LIKE '%Hotel%' THEN 1 END) AS "Hotel", 
    COUNT(CASE WHEN [TaxiHotelFood] LIKE '%Taxi%' THEN 1 END) AS "Food" 
    FROM [CSART].[dbo].[tblPatAdmission] 
    WHERE (TaxiHotelFood != '' AND TaxiHotelFood IS NOT NULL) 
    GROUP BY TaxiHotelFood

相反，它返回的是這樣的：

Taxis Hotel Food 
0   2  0 
1   1  1

它不會添加計數，除非該字段的內容相同。有沒有簡單的方法來解決這個問題？

來源

2016-03-07 user1834616

您能提供樣品數據和預期結果嗎？我沒有看到你的查詢有什麼問題。當你說'添加計數'時，你的意思是你只需要一行作爲結果（1,3,1）？如果是這樣，放棄'組'... – sgeddes

哇，真的不應該花了我一個多小時才弄清楚。謝謝，它現在正在工作。 – user1834616

您是否注意到第二個'％Taxi％'應該是'％Food％'？ –

SELECT 
COUNT(CASE WHEN [TaxiHotelFood] LIKE '%Taxi%' THEN 1 END) AS "Taxis", 
COUNT(CASE WHEN [TaxiHotelFood] LIKE '%Hotel%' THEN 1 END) AS "Hotel", 
COUNT(CASE WHEN [TaxiHotelFood] LIKE '%Taxi%' THEN 1 END) AS "Food" 
FROM [CSART].[dbo].[tblPatAdmission] 
WHERE (TaxiHotelFood != '' AND TaxiHotelFood IS NOT NULL) 
GROUP BY TaxiHotelFood 
UNION 
SELECT 
SUM(CASE WHEN [TaxiHotelFood] LIKE '%Taxi%' THEN 1 END) AS "Taxis", 
SUM(CASE WHEN [TaxiHotelFood] LIKE '%Hotel%' THEN 1 END) AS "Hotel", 
SUM(CASE WHEN [TaxiHotelFood] LIKE '%Taxi%' THEN 1 END) AS "Food" 
FROM [CSART].[dbo].[tblPatAdmission] 
WHERE (TaxiHotelFood != '' AND TaxiHotelFood IS NOT NULL) 
GROUP BY TaxiHotelFood

來源

2016-03-07 23:50:36

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