2013-07-21 53 views
0

我想要做的是使用Django窗體更新Dog模型中的現有行,但我遇到了一個錯誤。ModelForm不喜歡接收實例

我收到此錯誤:

__init__() got multiple values for keyword argument 'user' 

因爲Django的認爲這裏存在一個問題:

form = DogImageForm(request.POST, request.FILES, user=request.user, instance=instance) 

我model.py是

class DogImageForm(ModelForm): 
    dogs = forms.ModelChoiceField(queryset=Dog.objects.none()) 
    class Meta: 
     model = Dog 
     fields = ['dogs','image'] 

    def __init__(self, user, *args, **kwargs): 
     super(DogImageForm, self).__init__(*args, **kwargs) 
     userprofile = UserProfile.objects.get(user=user) 
     self.fields['dogs'].queryset = Dog.objects.filter(user=userprofile) 

而且我view.py是:

def dog_image_upload(request): 
    if request.user.is_authenticated(): 
     if request.method == 'POST': 

      userprofile = UserProfile.objects.get(user=request.user) 
      instance = Dog.objects.get(id=str(request.POST['dogs']))#user=userprofile, 

      form = DogImageForm(request.POST, request.FILES, user=request.user, instance=instance) 
      if form.is_valid(): 
       form.save() 
       reader = csv.reader(request.FILES['file']) 
       return HttpResponseRedirect('/members-dogs/') 
     else: 
      form = DogImageForm(user=request.user) 
     return render_to_response("dog-image-upload.html", {'form': form}, context_instance=RequestContext(request)) 
    else: 
     return HttpResponseRedirect('/') 

我本來停留在使用的ModelForm這裏Access request.user in modelForm

如果任何人有一個解決方案來解決這個我就超開心傳遞request.user!

回答

1

您正在通過request.POST作爲位置參數用戶,request.user作爲關鍵字參數用戶。你做類似如下:

>>> def f(user, *args, **kwargs): pass 
... 
>>> f('post', user='user') 
Traceback (most recent call last): 
    File "<stdin>", line 1, in <module> 
TypeError: f() got multiple values for keyword argument 'user' 
>>> f('user', 'post') 

而是做以下操作:

form = DogImageForm(request.user, request.POST, request.FILES, instance=instance) 
+0

感謝@falsetru奏效! –

+1

@AlexStewart,不客氣。我多次犯了這個錯誤;) – falsetru