我認爲真正的問題是您的關聯可能不正確。
,但你有什麼是
這並沒有什麼意義(至少在我見過課堂和學生互動的任何情況下)。您應該創建多對多關係,而不是Klass
和Student
之間的一對多關係。
class Student < ActiveRecord::Base
has_many :klasses, through: :student_klasses
has_many :student_klasses
end
class Klass < ActiveRecord::Base
has_many :students, through: :student_klasses
has_many :student_klasses
end
class StudentKlass < ActiveRecord::Base
belongs_to :student
belongs_to :klass
end
一旦你有了這些適當的正確的組織,你需要調用.joins
從Klass
類:students
關聯。你可以沒有範圍。
Klass.joins(:students).where("students.organization_id = ?", params[:id]).order('price DESC').limit(RESULT_SET_COUNT)
在ActiveRecord上閱讀the guide查詢。
這裏是證明(使用上面的確切型號定義)該協會的排序確實不問題。
irb(main):001:0> s = Student.create(name: "Deefour")
SQL (3.6ms) INSERT INTO "students" ("created_at", "name", "updated_at") VALUES (?, ?, ?) [["created_at", Fri, 08 Mar 2013 01:33:32 UTC +00:00], ["name", "Deefour"], ["updated_at", Fri, 08 Mar 2013 01:33:32 UTC +00:00]]
=> #<Student id: 1, name: "Deefour", created_at: "2013-03-08 01:33:32", updated_at: "2013-03-08 01:33:32">
irb(main):002:0> kk = []
=> []
irb(main):003:0> kk << Klass.create(title: "Klass 1")
SQL (0.3ms) INSERT INTO "klasses" ("created_at", "title", "updated_at") VALUES (?, ?, ?) [["created_at", Fri, 08 Mar 2013 01:34:06 UTC +00:00], ["title", "Klass 1"], ["updated_at", Fri, 08 Mar 2013 01:34:06 UTC +00:00]]
=> [#<Klass id: 1, title: "Klass 1", created_at: "2013-03-08 01:34:06", updated_at: "2013-03-08 01:34:06">]
irb(main):004:0> kk << Klass.create(title: "Klass 2")
SQL (0.3ms) INSERT INTO "klasses" ("created_at", "title", "updated_at") VALUES (?, ?, ?) [["created_at", Fri, 08 Mar 2013 01:34:14 UTC +00:00], ["title", "Klass 2"], ["updated_at", Fri, 08 Mar 2013 01:34:14 UTC +00:00]]
=> [#<Klass id: 1, title: "Klass 1", created_at: "2013-03-08 01:34:06", updated_at: "2013-03-08 01:34:06">, #<Klass id: 2, title: "Klass 2", created_at: "2013-03-08 01:34:14", updated_at: "2013-03-08 01:34:14">]
irb(main):005:0> s.klasses = kk
Klass Load (0.1ms) SELECT "klasses".* FROM "klasses" INNER JOIN "student_klasses" ON "klasses"."id" = "student_klasses"."klass_id" WHERE "student_klasses"."student_id" = ? [["student_id", 1]]
SQL (0.4ms) INSERT INTO "student_klasses" ("created_at", "klass_id", "student_id", "updated_at") VALUES (?, ?, ?, ?) [["created_at", Fri, 08 Mar 2013 01:34:29 UTC +00:00], ["klass_id", 1], ["student_id", 1], ["updated_at", Fri, 08 Mar 2013 01:34:29 UTC +00:00]]
SQL (0.1ms) INSERT INTO "student_klasses" ("created_at", "klass_id", "student_id", "updated_at") VALUES (?, ?, ?, ?) [["created_at", Fri, 08 Mar 2013 01:34:29 UTC +00:00], ["klass_id", 2], ["student_id", 1], ["updated_at", Fri, 08 Mar 2013 01:34:29 UTC +00:00]]
=> [#<Klass id: 1, title: "Klass 1", created_at: "2013-03-08 01:34:06", updated_at: "2013-03-08 01:34:06">, #<Klass id: 2, title: "Klass 2", created_at: "2013-03-08 01:34:14", updated_at: "2013-03-08 01:34:14">]
irb(main):006:0> Student.first.klasses.map(&:id)
Student Load (0.2ms) SELECT "students".* FROM "students" ORDER BY "students"."id" ASC LIMIT 1
Klass Load (0.1ms) SELECT "klasses".* FROM "klasses" INNER JOIN "student_klasses" ON "klasses"."id" = "student_klasses"."klass_id" WHERE "student_klasses"."student_id" = ? [["student_id", 1]]
=> [1, 2]
我是否還需要保持我在該範圍內的加入?目前它說它找不到學生表。我們在某處是否有語法錯誤?也許應該是學生而不是學生? – Bohn 2013-03-06 21:08:32
它說「沒有找到名爲'學生'的協會」 – Bohn 2013-03-06 21:18:16
它看起來像你的協會不完全是他們應該的。我已經更新了我的答案,以幫助指導您。 – deefour 2013-03-06 21:47:54