對提交檢查工作不

我剛纔發現isset功能不再工作在我的登錄和註冊形式的PHP isset功能。我很奇怪，所以我解開了我最近所做的一切，看它是否造成了它，但沒有運氣。如果我刪除isset並用此替換;對提交檢查工作不

if($_SERVER['REQUEST_METHOD'] == "POST"){

它的工作原理！但是我在一個頁面上有兩個表單，所以我需要檢查哪一個被提交。

這裏的isset功能：

if (isset($_POST['submit_login'])) {

而只是讓你知道它有正確的名稱提交按鈕;

<input type="submit" name="submit_login" value="Login" class="buttonClassic"/>

的一個註冊表單是完全一樣的，但用的名字submit_reg。

形式：

<form action="<?php echo htmlentities('Login'); ?>" method="post" id="login"> 
    <p class="p1">Already signed up? Log in</p><hr/> 
    <label for="email">Your email address </label><input type="email" required name="email" placeholder="Email" class="text" id="email"> 
    <label for="password">Your password </label><input type="password" name="pass" required placeholder="Password" class="text" id="password"> 
    <center><input type="submit" name="submit_login" value="Login" class="buttonClassic"/></center> 
    <div class="center-align-text"> 
     <p class="p3"><a href="passreset.html">Forgotten your password?</a></p> 
    </div> 
</form>

註冊表單：

<form action="<?php echo htmlentities('Login'); ?>" method="post" id="register" > 
    <p class="p1">New to NBS? Sign up, it's free!</p><hr/> 
    <label for="reg_email">What's your email address? </label><input type="email" name="email" required placeholder="Email" class="text" id="reg_email"> 
    <label for="reg_password">Choose a password </label><input type="password" required name="pass" placeholder="Password" class="text" id="reg_password"> 
    <label for="reg_password2">Re-type password </label><input type="password" required name="pass2" placeholder="Re-type password" class="text" id="reg_password2"> 
    <input type="checkbox" name="subscribed" value="subscribed" id="subscribed"><label for="subscribed">Yes, send me email updates from NewBorn Sounds. </label> 
    <br/> 
    <input type="checkbox" required="flag" name="terms" value="ticked" id="terms"><label for="terms">I agree to the <a href="Terms">terms & conditions</a>.</label> 

    <center><input type="submit" name="submit_reg" value="Sign Up" class="buttonClassic"></center> 
</form>

如果您有什麼需要更多就罵！

哦，我知道我可以只提交表單到外部的PHP腳本，但我並不特別想這樣做，因爲我想在用戶輸入錯誤將被輸出到同一頁。我知道我可以使用ajax，但我試圖將javascript作爲附加組件，而不是減少沒有js的用戶體驗。

HTML全文：

<div id="login_form_wrapper"> 

<form action="Login" method="post" id="login" novalidate="novalidate"> 
    <p class="p1">Already signed up? Log in</p><hr> 
    <label for="email">Your email address </label><input type="email" required="" name="email" placeholder="Email" class="text" id="email"> 
    <label for="password">Your password </label><input type="password" name="pass" required="" placeholder="Password" class="text" id="password"> 
    <center><input type="submit" name="submit_login" value="Login" class="buttonClassic"></center> 
    <div class="center-align-text"> 
     <p class="p3"><a href="passreset.html">Forgotten your password?</a></p> 
    </div> 
</form> 


<form action="Login" method="post" id="register" novalidate="novalidate"> 
    <p class="p1">New to NBS? Sign up, it's free!</p><hr> 
    <label for="reg_email">What's your email address? </label><input type="email" name="email" required="" placeholder="Email" class="text" id="reg_email"> 
    <label for="reg_password">Choose a password </label><input type="password" required="" name="pass" placeholder="Password" class="text" id="reg_password"> 
    <label for="reg_password2">Re-type password </label><input type="password" required="" name="pass2" placeholder="Re-type password" class="text" id="reg_password2"> 
    <input type="checkbox" name="subscribed" value="subscribed" id="subscribed"><label for="subscribed">Yes, send me email updates from NewBorn Sounds. </label> 
    <br> 
    <input type="checkbox" required="flag" name="terms" value="ticked" id="terms"><label for="terms">I agree to the <a href="Terms">terms &amp; conditions</a>.</label> 

    <center><input type="submit" name="submit_reg" value="Sign Up" class="buttonClassic"></center> 
</form> 

</div>

來源

2013-06-01 Jacob Windsor

'print_r（$ _ POST）;' – str

出於好奇，你有兩個單獨的嵌套表單嗎？ – Fabio

@Fabio yes表單完全獨立 –

形式的行動必須是一個有效的URL，例如「/login.php」。

複選框要麼給定的值（檢查一次），也不會出現在所有。最好是仔細檢查他們：「isset（$ _ POST [ 'mycheckbox']）& & '價值' == $ _ POST [ 'mycheckbox']」。

向我們展示您使用評估的形式PHP。

來源

2013-06-01 15:09:28

也許你可以做這樣的事情：

if($_SERVER['REQUEST_METHOD'] == "POST"){ 
if (isset($_POST['submit_login'])) { 
    //do something 
} else { 
    //do something else 
} 

}

來源

2013-06-01 15:20:22

如何呢？

<input type="submit" name="submit_reg" value="Sign Up" class="buttonClassic"> 
<?php 
if($_POST['submit'] == 'Sign Up'){ 
    //do something 
} 
?>

來源

2013-06-14 07:53:16 kathy

對提交檢查工作不

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