如何讀取.dat文件和grep的具體值

-3

我正在嘗試使用bash腳本來讀取.dat文件。如何讀取.dat文件和grep的具體值

該值包含文件大小我想grep大於0除第一列以外的值。大於零的值可以進入任何行。

I have awk script to read line by line. 



1349848860, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0 
1349848920, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0 
1349848980, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0 
1349849040, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0 
1349849100, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 1, 0, 0, 0, 0, 0, 0 
1349849160, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 1, 0, 227.736, 2, 0, 29378, 0, 0, 0, 0, 0 
1349849220, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0 
1349849280, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0 
1349849340, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0 
1349851200, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0 
1349851260, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0 
1349851320, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 1, 0, 0, 0, 0, 0, 0 
1349851380, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 1, 0, 227.736, 2, 0, 29620, 0, 0, 0, 0, 0 
1349851440, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0 
#!/bin/bash 
FILENAME=$1 

awk '{kount++;print kount, $0}  END{print "\nTotal " kount " lines read"}' $FILENAME 
awk '{print $13}' $FILENAME

所需的輸出 -

227.736, 2, 29378 
    227.736, 2, 29620

感謝您的幫助。納文

來源

2012-10-12 Naveen

你是什麼問題？你試圖grep什麼值？ – choroba

這個不清楚。你想在第一列之後檢索任何正整數嗎？請顯示您的預期輸出。 –

明確的答案爲一個不清楚的問題;） – pankar

從我個人理解，你想給grep所有包含比0或1以外的數字，不在該行的開頭數起第一個行號。如何

egrep ',.*([2-9]|[0-9.]{4,})' tmp.txt

這將打印，從你的榜樣，行

 
1349939700, 0, 0, 0, 0, 2, 0, 0, 0, 0, 0, 0, 14353, 1, 0, 450.03, 2, 0, 69832, 0, 0, 0, 0, 0 
1349939880, 0, 0, 0, 0, 2, 0, 0, 0, 0, 0, 0, 14353, 1, 0, 450.03, 1, 0, 68552, 0, 0, 0, 0, 0 
1349940000, 0, 0, 0, 0, 2, 0, 0, 0, 0, 0, 0, 14353, 1, 0, 450.03, 1, 0, 73826, 0, 0, 0, 0, 0

來源

2012-10-12 11:39:56 January

如果你想利用每13日（即14353）的內容，16日（即450.03）和19日（即69832），在該文件中的每一行（根據您的輸入）的列，然後嘗試以下方法：

awk < test.dat -F ', ' '{print $13,$16,$19}'

其中test.dat在您的數據文件。

這將輸出：

14353 450.03 69832 
0 0 0 
0 0 0 
14353 450.03 68552 
0 0 0 
14353 450.03 73826

來源

2012-10-12 11:42:51 pankar

如果我理解你的需求：

awk -F"," '{for (i=2;i<=NF;i++){if ($i > 1) {print}}}' file.dat

輸出

1349939700, 0, 0, 0, 0, 2, 0, 0, 0, 0, 0, 0, 14353, 1, 0, 450.03, 2, 0, 69832, 0, 0, 0, 0, 0 
1349939700, 0, 0, 0, 0, 2, 0, 0, 0, 0, 0, 0, 14353, 1, 0, 450.03, 2, 0, 69832, 0, 0, 0, 0, 0 
1349939700, 0, 0, 0, 0, 2, 0, 0, 0, 0, 0, 0, 14353, 1, 0, 450.03, 2, 0, 69832, 0, 0, 0, 0, 0 
1349939700, 0, 0, 0, 0, 2, 0, 0, 0, 0, 0, 0, 14353, 1, 0, 450.03, 2, 0, 69832, 0, 0, 0, 0, 0 
1349939700, 0, 0, 0, 0, 2, 0, 0, 0, 0, 0, 0, 14353, 1, 0, 450.03, 2, 0, 69832, 0, 0, 0, 0, 0 
1349939880, 0, 0, 0, 0, 2, 0, 0, 0, 0, 0, 0, 14353, 1, 0, 450.03, 1, 0, 68552, 0, 0, 0, 0, 0 
1349939880, 0, 0, 0, 0, 2, 0, 0, 0, 0, 0, 0, 14353, 1, 0, 450.03, 1, 0, 68552, 0, 0, 0, 0, 0 
1349939880, 0, 0, 0, 0, 2, 0, 0, 0, 0, 0, 0, 14353, 1, 0, 450.03, 1, 0, 68552, 0, 0, 0, 0, 0 
1349939880, 0, 0, 0, 0, 2, 0, 0, 0, 0, 0, 0, 14353, 1, 0, 450.03, 1, 0, 68552, 0, 0, 0, 0, 0 
1349940000, 0, 0, 0, 0, 2, 0, 0, 0, 0, 0, 0, 14353, 1, 0, 450.03, 1, 0, 73826, 0, 0, 0, 0, 0 
1349940000, 0, 0, 0, 0, 2, 0, 0, 0, 0, 0, 0, 14353, 1, 0, 450.03, 1, 0, 73826, 0, 0, 0, 0, 0 
1349940000, 0, 0, 0, 0, 2, 0, 0, 0, 0, 0, 0, 14353, 1, 0, 450.03, 1, 0, 73826, 0, 0, 0, 0, 0 
1349940000, 0, 0, 0, 0, 2, 0, 0, 0, 0, 0, 0, 14353, 1, 0, 450.03, 1, 0, 73826, 0, 0, 0, 0, 0

來源

2012-10-12 11:46:28

如何讀取.dat文件和grep的具體值

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